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a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
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a) \(\left(x-2018\right)\cdot3=0\)
\(\Leftrightarrow x-2018=0\)
\(\Leftrightarrow x=2018\)
b) \(25\left(x-8\right)=0\)
\(\Leftrightarrow x-8=0\)
\(\Leftrightarrow x=8\)
c) \(25+\left(15+x\right)=75\)
\(\Leftrightarrow15+x=50\)
\(\Leftrightarrow x=35\)
![](https://rs.olm.vn/images/avt/0.png?1311)
có tổng bằng 0 thì suy ra cả 2 số bằng nhau
còn có tích bằng 0 thì suy ra 1 trong 2 số bằng 0
Bạn cứ thế làm nhé
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a) -9-25=(7-x)-(25+7)
<=> −9−25=7−x−25−7
<=> -9=7-x-7
<=> -9=-x
<=> x=9
b) (x-5)(x+8)=0
<=> x-5=0 hoặc x+8=0
<=> x=5 hoặc x=-8
d) Đề sai, x đâu???
...
\(c,0< \left|x-7\right|< 3\)
\(0< x-7< 3\)
\(7< x< 10\)
\(\Rightarrow x\in\left\{8;9\right\}\)
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(-1).(-1)\(^2\).(-1)\(^3\).....(-1)\(^{100}\)
\(\Rightarrow\)(-1).1.(-1).1.....(-1).1
có tất cả 50 số -1
có tất cả 50 số 1
\(\Rightarrow\) \([\)(-1).50\(]\).\([\)1.50\(]\)
=-50.50=0
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1. Thực hiện phép tính bằng cách hợp lí :
a) (-46) + (-125) + 46 + 25 = [(-46)+46] + [(-125)+25]
= 0+(-100) = -100
b) 25.(-15) + 25.(-5) + (-20).75 = 25.[(-15)+(-5)] + (-20).75
= 25.(-20) + (-20).75 = (-20).(25+75) = (-20).100 = -2000
c) (-151)+(-37)+(-42)+(-63)+142 =(-151)+[(-37)+(-63)]+[(-42)+142]
= (-151) + [(-100) + 100] = -151
d)32+(-149)+(-311)+(-89)+(-51) = 32+[(-149)+(-51)] + [(-311)+(-89)]
= 32+[(-200)+(-400)] = 32+(-600) = -568
e)-65.(87-17)-87.(17-65) = (-65).87 - (-65).17 - 87.17 + 87.65
= (-65).87 + 65.17 - 87.17 + 87.65 = [(-65).87+87.65] + 65.(17-87)
= 65.(-70) = -4550
g) -43.(53-16) - 53.(16-43) = (-43).53 - (-43).16 - 53.16 + 53.43
= (-43).53 + 43.16 - 53.16 + 53.43 = [(-43).53+53.43] + 16.(43-53)
= 16.(-10) = -160
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a) \(x.9,1+x.1,9=26,4\)
\(\Rightarrow x.\left(9,1+1,9\right)=26,4\)
\(\Rightarrow x.11=26,4\)
\(\Rightarrow x=\dfrac{26,4}{11}=\dfrac{12}{5}\)
Vậy \(x=\dfrac{12}{5}\)
b) \(x.9,9+x:10=12,5\)
\(\Rightarrow x.9,9+x.\dfrac{1}{10}=12,5\)
\(\Rightarrow x.\left(9,9+\dfrac{1}{10}\right)=12,5\)
\(\Rightarrow x.10=12,5\)
\(\Rightarrow x=\dfrac{12,5}{10}=\dfrac{5}{4}\)
Vậy \(x=\dfrac{5}{4}\)
c) \(x:0,1-x:4-x.0,75=2,25\)
\(\Rightarrow x.\dfrac{1}{0,1}-x.\dfrac{1}{4}-x.0,75=2,25\)
\(\Rightarrow x.10-x.\dfrac{1}{4}-x.0,75=2,25\)
\(\Rightarrow x.\left(10-\dfrac{1}{4}-0,75\right)=2,25\)
\(\Rightarrow x.9=2,25\)
\(\Rightarrow x=\dfrac{2,25}{9}=\dfrac{1}{4}\)
Vậy \(x=\dfrac{1}{4}\)
d) \(x:0,25-x=51,6\)
\(\Rightarrow x.\dfrac{1}{0,25}-x=51,6\)
\(\Rightarrow x.4-x=51,6\)
\(\Rightarrow x.\left(4-1\right)=51,6\)
\(\Rightarrow x.3=51,6\)
\(\Rightarrow x=\dfrac{51,6}{3}=\dfrac{86}{5}\)
Vậy \(x=\dfrac{86}{5}\)
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a) ( x- 55 ) . 17 = 0
x - 55 = 0 : 17
x - 55 = 0
x = 0 + 55
x = 55
Vậy x = 55
b) 25 . ( x - 75 ) = 25
x - 75 = 25 : 25
x - 75 = 1
x = 1 + 75
x = 76
Vậy x = 76
c) ( x - 5 ) ( x - 7 ) = 0
=> x - 5 = 0 hoặc x - 7 = 0
x = 0 + 5 x = 0 + 7
x = 5 x = 7
Vậy \(x\in\left\{5;7\right\}\)
d) ( x -11 ) ( x + 17 ) = 0
=> x - 11 = 0 hoặc x + 17 = 0
x = 0 + 11 x = 0 - 17
x = 11 x = -17
Vậy \(x\in\left\{11;-17\right\}\)
3 . [ 25 - ( x - 10 ) ] - 75 = 0
3 . [ 25 - ( x - 10 ) ] = 75
25 - ( x - 10 ) = 75 : 3
25 - ( x - 10 ) = 25
x - 10 = 25 - 25
x - 10 = 0
x = 0 + 10
x = 10
Vậy x = 10
\(3\cdot\left[25-\left(x-10\right)\right]-75=0\)
\(3\cdot\left[25-\left(x-10\right)\right]=0+75\)
\(3\cdot\left[25-\left(x-10\right)\right]=75\)
\(25-\left(x-10\right)=75:3\)
\(25-\left(x-10\right)=25\)
\(x-10=25-25\)
\(x-10=0\)
\(x=0+10\)
\(x=10\)