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\(\dfrac{11}{21}>\dfrac{x+4}{21}>\dfrac{9}{21}\)
\(\Rightarrow x+4=10\)
\(\Rightarrow x=10-4\)
\(\Rightarrow x=6\)
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5/9 x a/b -11/21 = 4/21
\(\dfrac{5}{9}\times\dfrac{a}{b}=\dfrac{4}{21}+\dfrac{11}{21}\)
\(\dfrac{5}{9}\times\dfrac{a}{b}=\dfrac{15}{21}=\dfrac{5}{7}\)
\(\dfrac{a}{b}=\dfrac{5}{7}:\dfrac{5}{9}\)
\(\dfrac{a}{b}=\dfrac{5}{7}\times\dfrac{9}{5}\)
\(\dfrac{a}{b}=\dfrac{9}{7}\)
5/9.a/b=4/21+11/21
5/9.a/b=15/21
a/b=15/21:5/9
a/b=15/21.9/5
a/b=9/7
=> a=9 ; b=7
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a)\(\frac{8}{3}\)
b)\(\frac{1}{5}=0,2\)
c)\(\frac{17}{135}\)
d)\(\frac{2}{3}\)
e)\(\frac{5}{2}=2,5\)
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Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
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\(a,\dfrac{1}{12}\times\dfrac{4}{5}=\dfrac{1\times4}{12\times5}=\dfrac{1}{15}\)
\(b,\dfrac{40}{7}\times\dfrac{21}{5}=\dfrac{40\times21}{7\times5}=\dfrac{24}{1}=24\)
\(c,\dfrac{9}{5}\div\dfrac{4}{7}=\dfrac{9}{5}\times\dfrac{7}{4}=\dfrac{9\times7}{5\times4}=\dfrac{63}{20}\)
\(d,\dfrac{11}{24}\div\dfrac{44}{3}=\dfrac{11}{24}\times\dfrac{3}{44}=\dfrac{11\times3}{24\times44}=\dfrac{1}{32}\)
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Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13
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\(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\left(\dfrac{7}{11}+\dfrac{2}{11}\right)+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\dfrac{9}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{9}{11}\times\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{9}{11}\times1\)
\(=\dfrac{9}{11}\)
a) \(20,23\times21+20,23\times80-20,23\)
\(=20,23\times\left(21+80-1\right)\)
\(=20,23\times100\)
\(=2023\)
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\(\dfrac{21}{24}\cdot\dfrac{2}{11}:\dfrac{9}{8}=\dfrac{21}{24}\cdot\dfrac{2}{11}\cdot\dfrac{8}{9}=\dfrac{16}{99}\)
\(\dfrac{17}{9}\cdot\dfrac{5}{6}:\dfrac{12}{13}=\dfrac{17}{9}\cdot\dfrac{5}{6}\cdot\dfrac{13}{12}=\dfrac{1105}{648}\)
= 1/21.11/3
=11/63
ok bn