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A ) 2300 = ( 23)100=8100
3200 = ( 32)100= 9100
Nên 2300<3200
B)421 = (43)7=647
814= ( 82)7=647
Nên 814=421
a) \(2^{300}=2^{3\cdot100}=8^{100}\)
\(3^{200}=3^{2\cdot100}=9^{100}\)
vì \(8^{100}< 9^{100}\Rightarrow2^{300}< 3^{200}\)

31.(-18) + 31.(-81) - 31
= 31.(-18 - 81 - 1)
= 31.(-100) = -3100
-48 + 48.(-78) + 48.(-21) = 48.(-1 - 78 - 21) = 48. (-100) = -4800
-75.(8 - 65) - 65.(75 - 18) = -75.18 + 75.65 - 65.75 + 65.18 = 0
29.(19 - 13) - 19.(29 - 13) = 29.19 - 29.13 - 19.29 + 19.13 = 0
13.(23 + 22) - 3(17 + 28) = 13.25 - 3.45 = (10 + 3).25 - 3.45
= 10 . 25 + 3.25 - 3.45 = 10.25 - 3.(45 - 25)
= 250 - 3.20 = 250 - 60 = 190
(-25).21 . (-2)2.(|3|). (-1)2n + 2 (n \(\in\)N*)
= (-25. 4) . (21.3).1
= -100. 63 = -6300

\(31^{15}< 32^{15}=\left(2^5\right)^{15}=2^{75}\)
\(17^{19}>16^{19}=\left(2^4\right)^{19}=2^{76}\)
Do \(2^{75}< 2^{76}\Rightarrow31^{15}< 2^{75}< 2^{76}< 17^{19}\)
Vậy \(31^{15}< 17^{19}\)

Có \(17^{25}>17^{22}=\left(17^2\right)^{11}=289^{11}\)
Mà \(289^{11}>31^{11}\)=) \(17^{22}>31^{11}\Rightarrow17^{25}>17^{22}>31^{11}\Rightarrow17^{25}>31^{11}\)
=) \(31^{11}< 17^{25}\)

áp dụng định lĩ Pain " chất lượng hơn số lượng " ta có
\(8^9< 9^8\)
\(12^{19}< 18^{20}\)
\(25^{24}>26^{25}\)
Ta có :
Cơ số : 17 < 18
Mũ số : 19 < 20
=> \(17^{19}< 18^{20}\)
Ta có :
Cơ số : 25 < 26
Mũ số : 24 < 25
=> \(25^{24}< 26^{25}\)


Câu 1:
a) Ta có: 2n+1 là số lẻ∀n
⇒\(\left(-1\right)^{2n+1}=-1\)
Ta có: \(\left(-25\right)\cdot21\cdot\left(-2\right)^2\cdot\left(-\left|-3\right|\right)\cdot\left(-1\right)^{2n+1}\)
\(=-25\cdot21\cdot4\cdot\left(-3\right)\cdot\left(-1\right)\)
\(=75\cdot84\cdot\left(-1\right)\)
\(=-6300\)
b) Ta có: \(\left(-5\right)^3\cdot67\cdot\left(-\left|-2^3\right|\right)\cdot\left(-1\right)^{2n}\)
\(=-125\cdot67\cdot\left(-8\right)\)
\(=1000\cdot67=67000\)
c) Ta có: \(35\cdot18-5\cdot7\cdot28\)
\(=35\cdot18-35\cdot28\)
\(=35\cdot\left(18-28\right)=35\cdot\left(-10\right)=-350\)
d) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-24\cdot16+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)=5\cdot\left(-8\right)=-40\)
e) Ta có: \(29\cdot\left(19-13\right)-19\cdot\left(19-13\right)\)
\(=6\cdot\left(29-19\right)=6\cdot10=60\)
g)Sửa đề: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
Ta có: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\cdot\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
h) Ta có: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=-12\cdot\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
k) Ta có: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot\left(13-3\right)=45\cdot10=450\)
m) Ta có: \(-48+48\cdot\left(-78\right)+48\cdot\left(-21\right)\)
\(=48\cdot\left(-1-78-21\right)\)
\(=48\cdot\left(-100\right)=-4800\)
n) Ta có: \(135\cdot\left(171-123\right)-171\cdot\left(135-123\right)\)
\(=135\cdot171-135\cdot123-171\cdot135+171\cdot123\)
\(=123\cdot\left(-135+171\right)=123\cdot36=4428\)
\(31^{15}< 32^{15}=\left(2^5\right)^{15}=2^{75}\)
\(17^{19}>16^{19}=\left(2^4\right)^{19}=2^{76}\)
\(2^{75}< 2^{76}va\) \(31^{15}< 2^{75},17^{19}>2^{76}\)
\(=>31^5< 17^{19}\)