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\(e,112-45+5x=87\)
\(67+5x=87\)
\(5x=20\)
\(x=4\)
\(f,6^2+64:\left(x-1\right)=52\)
\(36+64:\left(x+1\right)=52\)
\(64:\left(x+1\right)=16\)
\(x+1=4\)
\(x=3\)
\(a,56-36:\left(-9\right)+3.\left(-2\right)^2\)
\(=56+4+12=72\)
\(b,36-16\left[2\left(14-15\right)^{21}\right]+14\)
\(=36-12\left[2-\left(-1\right)^{21}\right]+14\)
\(=36-16\left(2+1\right)+14\)
\(=36-48+14=2\)
\(c,2\left(-3\right)^2-3\left(-2\right)^3.\left(-2\right)^3+8\)
\(=2.9-3.8.8+8=218\)
\(d,\left(-8\right)25\left(-2\right)4\left(-5\right)125=\left(-8\right)125\left(-2\right)\left(-5\right)25.4=-1000.10.100=-1000000\)
\(56-36:\left(-9\right)+3.\left(-2\right)^2\)
\(=56+4+3.4\)
\(=60+12=72\)
\(36-16.\left|2-\left(14-15\right)^{21}\right|+14\)
\(=36-16.\left(2+1\right)+14\)
\(=36-48+14=2\)
\(2.\left(-3\right)^2-3.\left(-2\right)^3.\left(-2\right)^3+8\)
\(=2.9-3.8.8+8\)
\(=18-192+8=-166\)
\(\left(-8\right).25.\left(-2\right).4.\left(-5\right).125\)
\(=\left[\left(-8\right).125\right].\left(25.4\right).\left[\left(-5\right).\left(-2\right)\right]\)
\(=\left(-1000\right).100.\left(-10\right)=1000000\)
câu 1)
\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2)
\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)
\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4)
\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5)
\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6)
\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7)
\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8)
\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9)
\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10)
\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11)
\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12)
\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13)
\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14)
\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15)
\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16)
\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)
\(a,3.\left(2x+8\right)-\left(5x+2\right)=0\)
\(\Rightarrow6x+24-5x+2=0\)
\(\Rightarrow6x-5x=0-24-2\)
\(\Rightarrow x=-26\)
\(5.\left(7-3x\right)+7.\left(2+2x\right)=0\)
\(\Rightarrow35-15x+14+14x=0\)
\(\Rightarrow-15x+14x=0-35-14\)
\(\Rightarrow-x=-49\)
\(\Rightarrow x=49\)
Tìm x
a, 3.(2x + 8) - (5x + 2)=0 ............. Hok Tốt nhé ..............
\(\Leftrightarrow3x+24-5x-2=0\) ........ Nhớ k cho mik nhé .........
\(\Leftrightarrow x+22=0\)
\(\Rightarrow x=-22\)
b, 5.(7 - 3x) + 7.( 2 + 2x)
\(\Leftrightarrow35-15x+14+14x\)
\(\Leftrightarrow-15x+14x=0-35-14\)
\(\Leftrightarrow-x=-49\)
\(\Rightarrow x=49\)
a)\(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
\(5^{2x-3}-2\cdot25=75\)
\(5^{2x-3}-50=75\)
\(5^{2x-3}=125\)
\(125=5^3\)
\(5^3=5^{\left(3+3\right):2}=5^3\Rightarrow x=3\)
Vậy \(x=3\)
b)\(\frac{2}{9}\cdot\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(=\frac{2}{9}\cdot\left(5x+1\right):2=\frac{5}{36}+\frac{1}{18}\)
\(=\frac{2}{9}\cdot\left(5x+1\right)=\frac{7}{36}\cdot2\)
\(5x+1=\frac{7}{18}:\frac{2}{9}\)
\(x=\left(\frac{7}{4}-1\right):5=\frac{3}{20}\)
\(\Rightarrow x=\frac{3}{20}\)
a, \(5^{2x-3}-2.5^2=5^2.3\)
\(\Leftrightarrow5^{2x-3}-2.25=25.3\)
\(\Leftrightarrow5^{2x-3}-50=75\)
\(\Leftrightarrow5^{2x-3}=125\)
\(\Leftrightarrow5^{2x-3}=5^3\)
\(\Leftrightarrow2x-3=3\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
b, \(\frac{2}{9}.\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right):2=\frac{7}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{36}.2\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{18}\)
\(\Leftrightarrow5x+1=\frac{7}{18}:\frac{2}{9}\)
\(\Leftrightarrow5x+1=\frac{7}{18}.\frac{9}{2}\)
\(\Leftrightarrow5x+1=\frac{7}{4}\)
\(\Leftrightarrow5x=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}:5=\frac{3}{4}.\frac{1}{5}=\frac{3}{20}\)
5x-8= 36:3
5x-8= 12
5x=12 +8
5x=20
x=20:5
x=4
x=4