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\(c.x\left(\frac{2}{5}-\frac{3}{5}\right)=\frac{2}{35}\)
\(x=\frac{2}{35}:\frac{-1}{5}=-\frac{2}{7}\)
\(d.\left(2x+1\right)^2=49=7^2=\left(-7\right)^2\)
\(TH1:2x+1=7\Rightarrow x=3\)
\(TH2=2x+1=-7\Rightarrow x=-4\)
\(a.x=\frac{-3}{5}-\frac{4}{9}=\frac{-47}{45}\)
\(b.\frac{3}{5}:x=\frac{17}{10}-\frac{2}{5}\)
\(x=\frac{3}{5}:\frac{13}{10}=\frac{6}{13}\)
\(\frac{-5}{x}=\frac{-y}{8}=\frac{18}{72}\)
\(\Leftrightarrow\frac{-5}{x}=\frac{-y}{8}=\frac{1}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}-\frac{5}{x}=\frac{1}{4}\\-\frac{y}{8}=\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-5.4:1\\-y=8.1:4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-20\\-y=2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-20\\y=-2\end{cases}}}\)
vậy x=-20 và y=-2
Đặt \(A=\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+..+\frac{5}{100.102}\)
\(\frac{2}{5}A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{3}{6.8}+...+\frac{2}{100.102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{100}-\frac{1}{102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{102}\)
\(A=\frac{25}{51}:\frac{2}{5}\)
\(A=\frac{125}{102}\)
Ủng hộ mk nha !!! *_*
\(\text{Đ}\text{ặt}:A=\frac{5}{2.4}+\frac{5}{4.6}+\frac{5}{6.8}+..+\frac{5}{100.102}\)
\(\frac{2}{5}A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{3}{6.8}+...+\frac{2}{100.102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{100}-\frac{1}{102}\)
\(\frac{2}{5}A=\frac{1}{2}-\frac{1}{102}\)
\(A=\frac{25}{51}:\frac{2}{5}\)
\(A=\frac{125}{102}\)
\(C=\frac{5}{x-2}\)
\(\Rightarrow x-2\) thuộc Ư (5) = {-1;1;-5;5}
- \(x-2=-1\Rightarrow x=1\)
- \(x-2=1\Rightarrow x=3\)
- \(x-2=-5\Rightarrow x=-3\)
- \(x-2=5\Rightarrow x=7\)
Mà x nguyên nhỏ nhất.
Vậy: x = -3
=> x -2\(\in\) Ư(5)
x-2=1
x=1+2=3
x-2=5
x=5+2=7
x-2=-1
x=2+-1=1
x-2=-5
x=-5+2=-3
1) 120 + 20 : 4 - 22.3
=> 120 + 5 - 12
=> 125-12
=>113
2) ( 120 + 20 ) : 4 - 22 . 3
=> 140 : 4 - 12
=> 35 - 12
=> 23
3) 120 + ( 20 : 4 - 22 ).3
=> 120 + 1 . 3
=> 120 + 3
=> 123
1)120+20:4-2\(^2\) .3=120+5-4.3=120+5-12=113
2)(120+20):4-2\(^2\) .3=140:4-4.3=35-12=23
3)120+(20:4-2\(^2\) ).3=120+(5-4).3=120+1.3=120+3=123
\(2^x\cdot5=120\)
\(\Rightarrow2^x=24\)
\(\Rightarrow x=???\)
\(2^x.5=120\)
\(2^x=120:5\)
\(2^x=24\)
=>\(x=24:2\)
\(=12\)