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1.
2|x-6|+7x-2=|x-6|+7x
2|x-6| - |x-6|=7x-(7x-2)
|x-6| = 2
=>x-6 = +2
*x-6=2 *x-6 = -2
x =2+6 x = (-2)+6
x =8 x = 4
2.
|x-5|-7(x+4)=5-7x
|x-5|-7x-28 =5-7x
|x-5|-28 =5-7x+7x
|x-5|-28 = 5
|x-5| = 5+28
|x-5| = 33
=>x-5 = +33
*x-5=33 *x-5=-33
x =38 x = -28
3.
3|x+4|-2(x-1)=7-2x
3|x+4|-2x+2 =7-2x
3|x+4|-2 =7-2x+2x
3|x+4|-2 =7
3|x+4| =7+2
3|x+4| = 9
|x+4| =9:3
|x+4| = 3
=>x+4 = +3
*x+4=3 *x+4=-3
x =-1 x = -7
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20 - 2.(x+4) = 4
2.(x+4) = 20 - 4
2.(x+4) = 16
x+4 = 16 : 2
x+4 = 8
x = 8 - 4
x = 4
2(x-1):3=43 + 23
2(x-1):3= 64 + 8
2(x-1):3= 72
2(x-1) = 72 x 3
2(x-1) = 216
x - 1 = 216 : 2
x - 1 = 108
x = 108 + 1
x = 109
Hok tốt !
20-2(x+4)=4
2(x+4)=20-4
2(x+4)=16
x+4=16:2
x+4=8
x=8:4
x=2
Vậy x=2
12(x-1):3=43+23
12(x+1):3=64+8
12(x+1):3=72
12(x+1)=72.3
12(x+1)=216
x+1=216:12
x+1=18
x=18-1
x=17
Vậy x=17
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Đặt A = 1.2 + 2.3 + 3.4 + ... + 38.39 + 39.40
=> 3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 38.39.(40 - 37) + 39.40.(41 - 38)
= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 38.39.40 - 37.38.39 + 39.40.41 - 38.39.40
= 39.40.41 = 63960
=> A = 63960 : 3 = 21320
1 x 40 x (2 x 2) + (3x2) + (4x2) +...+ ( 39 x 2)
1 x 40 x (2 + 3 + 4 + .... + 39) x 2
40 x 779 x 2
31160 x 2
62320
k nha
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(\(\frac{3}{4}\). x ): \(\frac{1}{2}\)=\(\frac{4}{5}\)
x = \(\frac{4}{5}\).\(\frac{1}{2}\)
x = \(\frac{4}{10}\)= \(\frac{2}{5}\)
x = \(\frac{2}{5}\): \(\frac{3}{4}\)
x = \(\frac{8}{15}\)
hok tốt
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Bài giải
\(x\left(x+1\right)=2+4+6+...+20=\frac{\left[\left(20-2\right)\text{ : }2+1\right]\left(20+2\right)}{2}=10\cdot11=\left(-11\right)\cdot\left(-10\right)\)
\(\Rightarrow\text{ }x\in\left\{-11\text{ ; }10\right\}\)
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Ta có : |x + 7| = |-15|
<=> |x + 7| = 15
\(\Leftrightarrow\orbr{\begin{cases}x+7=15\\x+7=-15\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=15-7\\x=-15-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=8\\x=-22\end{cases}}\)
a) | x + 7 | = | -15 |
=> | x + 7 | = 15
=> x + 7 = 15 hoặc x + 7 = -15
+) x + 7 = 15 => x = 8
+) x + 7 = -15 => x = -22
Vậy x = 8 hoặc x = -22
b) 19 - | x - 1 | = 4
=> | x - 1 | = 15
=> x - 1 = 15 hoặc x - 1 = -15
+) x - 1 = 15 => x = 16
+) x - 1 = -15 => x = -14
Vậy x = 16 hoặc x = -14
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\(4^{x+2}+5.4^x=84\Rightarrow4^x\left(4^2+5\right)=84\Rightarrow4^x=4^1\Rightarrow x=1\)
(2+x).2=4
2+x=4:2
2+x=2
x=2-2
x=0
( 2 + x ) . 2 = 4
2 + x = 4 : 2
2 + x = 2
x = 2 - 2
x = 0
_HT_