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7 tháng 12 2022
\(\Leftrightarrow\left(2x-7\right)^{2017}\left[\left(2x-7\right)^2-1\right]=0\)
=>(2x-7)(2x-6)(2x-8)=0
hay \(x\in\left\{3;\dfrac{7}{2};4\right\}\)
27 tháng 12 2021
\(\Leftrightarrow\left(2x-3\right)\left(2x-\dfrac{7}{2}\right)\left(2x-\dfrac{5}{2}\right)=0\)
\(\Leftrightarrow x\in\left\{\dfrac{3}{2};\dfrac{7}{4};\dfrac{5}{4}\right\}\)
DP
2
11 tháng 12 2022
=>(2x-7)^2017[(2x-7)^2-1]=0
=>(2x-7)(2x-8)(2x-6)=0
hay \(x\in\left\{3;3.5;4\right\}\)
LT
0
LT
2
K
5 tháng 5 2018
\(\dfrac{x-2017}{2019}+\dfrac{x-2019}{2017}=\dfrac{x+6}{2021}\)
\(\Rightarrow\dfrac{x-2017}{2019}-1+\dfrac{x-2019}{2017}-1=\dfrac{x+6}{2021}-2\)
\(\Rightarrow\dfrac{x-2017}{2019}-\dfrac{2019}{2019}+\dfrac{x-2019}{2017}-\dfrac{2017}{2017}=\dfrac{x+6}{2021}-\dfrac{4042}{2021}\)
\(\Rightarrow\dfrac{x-2017-2019}{2019}+\dfrac{x-2019-2017}{2017}=\dfrac{x+6-4042}{2021}\)
\(\Rightarrow\dfrac{x-4036}{2019}+\dfrac{x-4036}{2017}=\dfrac{x-4036}{2021}\)
\(\Rightarrow\dfrac{x-4036}{2021}-\dfrac{x-4036}{2019}-\dfrac{x-4036}{2017}=0\)
\(\Rightarrow\left(x-4036\right)\left(\dfrac{1}{2021}-\dfrac{1}{2019}-\dfrac{1}{2017}\right)=0\)
=> x - 4036 = 0
=> x = 4036
MC
8 tháng 5 2018
x − 2017/2019 + x−2019/2017 = x+6/2021
=> x − 2017/2019 + x−2019/2017 = x+6/2021
=> x − 2017/2019 − 1 + x − 2019/2017 − 1 = x + 6/2021 − 2
=> x − 2017/2019 − 1 + x − 2019/2017 − 1 = x + 6/2021 − 2
=> x − 2017/2019 − 2019/2019 + x − 2019/2017 − 2017/2017
= x + 6/2021 − 4042/2021
=> x − 2017/2019 − 2019/2019 + x − 2019/2017 − 2017/2017
= x + 6/2021 − 4042/2021
=> x − 2017 − 2019/ 2019 + x − 2019 − 2017/2017
= x + 6 − 4042/2021
=> x − 2017 − 2019/2019 + x − 2019 − 2017/2017 = x + 6 − 4042/2021
=> x − 4036/2019 + x − 4036/2017 = x − 4036/2021
=> x − 4036/2019 + x − 4036/2017 = x − 4036/2021
=> x − 4036/2021 − x − 4036/2019 − x − 4036/2017 = 0
=> x − 4036/2021 − x − 4036/2019 − x − 4036/2017 = 0
=>(x − 4036)(12021 − 12019 − 12017) = 0
=> x - 4036 = 0
=> x = 4036
|2x+2017|=2019
=>\(|^{2x+2017=2019}_{2x+2017=-2019}\)
=>\(|^{2x=2019-2017}_{2x=-2019-2017}\)
=>\(|^{2x=2}_{2x=-4036}\)
=>\(|^{x=2:2}_{x=-4036:2}\)
=>\(|^{x=1}_{x=-2018}\)
Vậy x\(\in\left\{1;-2018\right\}\)
Chúc bn học tốt!
|2x + 2017|= 2019
\(\Rightarrow\)2x + 2017 = 2019 & 2x + 2017 = -2019
TH1: 2x + 2017 = 2019
2x = 2019 - 2017
2x = 2
x = 2 ÷ 2
x = 1
TH2: 2x + 2017 = -2019
2x = -2019 - 2017
2x = - 4036
x = -4036 ÷ 2
x = - 2018
Vây x \(\in\){ 1 ; -2018}