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a.23x +1=128
= 23x x 2=128
=128:2=64=2 mũ 6
vậy x=2
b.(7x-11)3=25+52+200
(7x-11)3=257=6,3579 mũ 3
7x=17,3579
x=2,4797
c.(2x+1)+(2x+2)+(2x+3)+...+(2x+101)=5757
vế trái có 101 số hạng
VT =(2x +1+2x+101).101:2=(4x+102).101:2=5757
(4x+102).101 =5757.2=11514
(4x+102)=11514:101=114
4x=114-102=12
x=12:4=3
vậy x=3
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720:[41-(2x-5)]=2^3.5
720:[41-2x+5]=40
[41+5-2x]=720:40
46-2x=18
2x=46-18
2x=28
x=14
a, 2x.4=128
2x=128:4
2x=32
2x=25
x=5
Vay x=5
b, x15=x
x=1
Vay x=1
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Mình làm được mỗi câu đầu à!!!!
16x < 1284
= ( 24 )x < ( 27)4
= 24x < 228
= 4x < 28
=> x < 7
Vậy x ∈ { 0; 1; 2; 3; 4; 5; 6 }.
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\(2^x.4=128;2^x.2^2=2^7;x=5\)
\(\left(2x+1\right)^3=125;2x+1=5;2x=4;x=2\)
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Ta có : Ư(90) = { 1;2;3;5;6;9;10;45;30;18;15;90 }
Ư(128) = { 1, 2, 4, 8, 16, 32, 64,128 }
Suy ra ƯC( 90;128 ) = { 1;2 }
Vậy ƯCLN( 90;128 ) = 2
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1/
Ta có: 90 = 2.32.5
128 = 27
=> ƯCLN = 2
Và BCNN = 27.32.5 = 5760
2/ a/ 6x - 128 = 6420 : 50
6x - 128 = 128,4
6x = 128,4 + 128 = 256,4
=> x = 256,4 : 6 = \(\frac{641}{15}\)
b/ 2x - 32 = 23 . 32
2x - 32 = 8.9 = 72
2x = 72 + 32 = 104
x = 104 : 2 = 52
bài 1 :
ta có : 90 = 2 . 3^2 .5
128 = 2^7
=> ƯCLN(90,128) = 2
=> BCNN(90,128) = 2^7 . 3^2 . 5 = 5760
bài 2 : tìm x
a) 6x - 128 = 6420 : 50
=> 6x - 128 = 128,4
=> 6x = 128,4 + 128
=> 6x = 256,4
=> x = 256,4 : 6
=> x = 641/15 ( chú ý : dấu / là phân số nha ! )
Vậy x = 641/15
b ) 2x - 32 = 2^3 . 3^2
=> 2x - 32 = 8.9
=> 2x - 32 = 72
=> 2x = 72 + 32
=> 2x = 104
=> x = 104:2
=> x = 52
Vậy x = 52
bài 3 :
a) 4.5^2 . 3^2 . 3^3
= 4 . 25 . 9 . 27
= 100 . 243
= 24300
b) 28.95 + 28 . 5 + 72 . 4
= 28 . ( 95 + 5 ) + 72 . 4
= 28 . 100 + 72 . 4
= 2800 + 72 : 4
= 2872 : 4
= 718
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a) 19992x - 6 = 1
19992x - 6 = 19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b) 2x x 4 = 128
2x=128:4
2x=32
2x=25
=>x=5
c) ( 2x + 1 ) 3 = 125
( 2x + 1 ) 3 = 53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2
a)19992x-6=1
19992x-6=19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b)2x.4=128
2x=128:4
2x=32
x=32:2
x=5
c)(2x+1)3=125
(2x+1)3=53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2