Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
(2x - 7)3 = 125
(2x - 7)3 = 53
cùng bỏ đi mũ 3
2x - 7 = 5
2x = 5 + 7
2x = 12
x = 12 : 2
x = 6
Bằng 6 nha
(2x - 7)3 = 125
\(\Rightarrow\)(2x - 7)3 = 53
\(\Rightarrow\)2x - 7 = 5
\(\Rightarrow\)2x = 12
\(\Rightarrow\)x = 6
a: =>2x+10-11 chia hết cho x+5
=>\(x+5\in\left\{1;-1;11;-11\right\}\)
=>\(x\in\left\{-4;-6;6;-16\right\}\)
b: =>2n+6-7 chia hết cho n+3
=>\(n+3\in\left\{1;-1;7;-7\right\}\)
=>\(n\in\left\{-2;-4;4;-10\right\}\)
a: =17-43=-26
b: =-34+34+11-11+105=105
c: \(=64+125\cdot100=12564\)
d: \(=60+\left[7^3-343\right]\cdot2017^{2018}=60\)
a, 17-229+17-25+229 b. 125 - 679 + 145 - 125 + 679
= ( 17-17) + ( 229 - 229)+25 = ( 125 - 125) + ( 679 - 679) + 145
= 0+0+25
= 25
\(a,\left(2y+1\right)^3=125\)
\(\Leftrightarrow2y+1=\sqrt[3]{125}=5\)
\(\Leftrightarrow2y=5-1=4\)
\(\Rightarrow y=2\)
\(b,\left(y-5\right)^4=\left(y-5\right)^6\)
\(\Leftrightarrow\left(y-5\right)^4-\left(y-5\right)^6=0\)
\(\Leftrightarrow\left(y-5\right)^4\left[1-\left(y-5\right)^2\right]=0\)
\(\Leftrightarrow\left(y-5\right)^4\left(1-y+5\right)\left(1+y-5\right)=0\)
\(\Leftrightarrow\left(y-5\right)^4\left(6-y\right)\left(y-4\right)=0\)
Vì \(\left(y-5\right)^4>0\forall y\)
\(\Rightarrow\left[{}\begin{matrix}6-y=0\\y-4=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}y=6\\y=4\end{matrix}\right.\)
a) \(\left(2y+1\right)^3=125\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2y+1\right)^3=5^3\\\left(2y+1\right)^3=\left(-5\right)^3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2y+1=5\\2y+1=-5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2y=4\\2y=-6\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=2\\y=-3\end{matrix}\right.\)
Vậy ...................
( 2x + 1 ) 3 = 125
( 2x + 1 ) 3 = 53
2x + 1 = 5
2x = 5 - 1
2x = 4
x = 4 : 2
x = 2
(2X+1)3=125
=>(2X+1)3=53
=>2x+1=5
=>2x=5-1
=>2X=4
=>X=4:2
=>x=2.