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a) 1 + 3 + 5 + 7 + ... + (2x - 1) = 225
(2x - 1 + 1) . [(2x - 1 - 1) : 2 + 1] : 2 = 225
2x.[(2x - 2) : 2 + 1] : 2 = 225
x . (x - 1 + 1) = 225
x . x = 225
=> x = 15

f) \(\frac{2x-1}{21}=\frac{3}{2x+1}\)( ĐKXĐ : \(x\ne-\frac{1}{2}\))
\(\Leftrightarrow\left(2x-1\right)\left(2x+1\right)=21\cdot3\)
\(\Leftrightarrow4x^2-1=63\)
\(\Leftrightarrow4x^2=64\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x^2=\left(\pm4\right)^2\)
\(\Leftrightarrow x=\pm4\)(tmđk)
h) \(\frac{10x+5}{6}=\frac{5}{x+1}\)( ĐKXĐ : \(x\ne-1\))
\(\Leftrightarrow\left(10x+5\right)\left(x+1\right)=6\cdot5\)
\(\Leftrightarrow10x^2+15x+5=30\)
\(\Leftrightarrow10x^2+15x+5-30=0\)
\(\Leftrightarrow10x^2+15x-25=0\)
\(\Leftrightarrow5\left(2x^2+3x-5\right)=0\)
\(\Leftrightarrow2x^2+3x-5=0\)
\(\Leftrightarrow2x^2-2x+5x-5=0\)
\(\Leftrightarrow2x\left(x-1\right)+5\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x+5\right)\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\2x+5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-\frac{5}{2}\end{cases}}\)(tmđk)
f) \(\frac{2x-1}{21}=\frac{3}{2x+1}\)
\(\Leftrightarrow\left(2x-1\right)\left(2x+1\right)=21.3\)
\(\Leftrightarrow4x^2-1=63\)
\(\Leftrightarrow4x^2=64\)
\(\Leftrightarrow x^2=16\)\(\Leftrightarrow x^2=4^2\)\(\Leftrightarrow x=4\)
Vậy \(x=4\)
h) \(\frac{10x+5}{6}=\frac{5}{x+1}\)
\(\Leftrightarrow\left(10x+5\right)\left(x+1\right)=5.6\)
\(\Leftrightarrow5\left(2x+1\right)\left(x+1\right)=30\)
\(\Leftrightarrow\left(2x+1\right)\left(x+1\right)=6\)
\(\Leftrightarrow2x^2+3x+1=6\)
\(\Leftrightarrow2x^2+3x-5=0\)
\(\Leftrightarrow\left(2x^2-2x\right)+\left(5x-5\right)=0\)
\(\Leftrightarrow2x\left(x-1\right)+5\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x+5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\2x+5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\2x=-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{-5}{2}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{2};1\right\}\)

a) | 5/4x -7/2| - | 5/8x + 3/5| = 0
|5/4x - 7/2| = | 5/8x + 3/5|
TH1: 5/4x - 7/2 = 5/8x + 3/5
=> 5/4x - 5/8x = 3/5 +7/2
5/8x = 41/10
x = 41/10:5/8
x = 164/25
TH2: 5/4x - 7/2 = -5/8x - 3/5
=> 5/4x + 5/8x = -3/5 +7/2
15/8x = 29/10
x = 29/10 : 15/8
x = 116/75
KL: x = 164/25 hoặc x = 116/75
các bài cn lại b lm tương tự nha! h lm dài lắm!

A) 149 - ( 2x - 53 ) = 54
2x - 53 = 149 - 54
2x - 53 = 95
2x = 95 + 53
2x = 148
x = 148 : 2
x = 74
B) 47 - 3( 2x - 18 ) = 35
3( 2x - 18 ) = 47 - 35
3( 2x - 18 ) = 12
2x - 18 = 12 : 3
2x - 18 = 4
2x = 4 + 18
2x = 22
x = 22 : 2
x = 11
C) 2x - 105 : 21 = 15
2x - 5 = 15
2x = 15 + 5
2x = 20
x = 20 : 2
x = 10
D) ( 2x - 105 ) : 21 = 15
2x - 105 = 15 x 21
2x - 105 = 315
2x = 315 + 105
2x = 420
x = 420 : 2
x = 210

\(257-\left(3x+25\right)=157\)
\(3x+25=257-157\)
\(3x+25=100\)
\(3x=75\)
\(x=25\)
vay \(x=25\)
\(x-140:35=270\)
\(x-4=270\)
\(x=274\)
vay \(x=274\)
\(23-\left(x:13\right)=18\)
\(\frac{x}{13}=5\)
\(\frac{x}{13}=\frac{65}{13}\)
\(\Rightarrow x=65\)
vay \(x=65\)
\(9\left(x+5\right)-13=671\)
\(9x+45=684\)
\(9x=639\)
\(x=71\)
vay \(x=71\)
\(9\left(4x\right)-13=24\)
\(36x=37\)
\(x=\frac{37}{36}\)
vay \(x=\frac{37}{36}\)
\(\left(x-5\right)-34:17=1\)
\(\left(x-5\right)-2=1\)
\(x-5=3\)
\(x=8\)
vay \(x=8\)
\(\left(2x-7\right).3=3\)
\(2x-7=1\)
\(2x=8\)
\(x=4\)
vay \(x=4\)
\(\left(3x-5\right):2=4.5\)
\(\left(3x-5\right):2=20\)
\(3x-5=10\)
\(3x=15\)
\(x=5\)
vay \(x=5\)
con lai lam tuong tu
mk moi tay roi nen ban tu lam vay
\(\Leftrightarrow11.2x+\left(1+3+5+...+21\right)=671\)
\(\Leftrightarrow22x+\frac{\left(21+1\right).11}{2}=671\)
\(\Leftrightarrow22x+\frac{22.11}{2}=671\Leftrightarrow22x+11.11=671\)
\(\Leftrightarrow22x=550\Leftrightarrow x=25\)