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x^2 - 1 = 80
=> x^2 = 80 + 1
=> x^2 =81
=> x^2 =9^2
=> x = 9
Vậy x = 9
![](https://rs.olm.vn/images/avt/0.png?1311)
2x+2x+1+2x+2+...+2x+2015=22019−82x+2x+1+2x+2+...+2x+2015=22019−8
⇒2x(1+2+22+...+22015)=22019−8⇒2x(1+2+22+...+22015)=22019−8
⇒2x(22016−1)=22019−8⇒2x(22016−1)=22019−8
⇒2x=22019−822016−1⇒2x=22019−822016−1
⇒2x=⇒2x=23.(22016−1)22016−123.(22016−1)22016−1
⇒2x=23⇒2x=23
⇒x=3⇒x=3
Vậy x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
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a/ 5.(x+1)2=80
(x+1)2=80:5
(x+1)2=16
=>x+1=4 ; x+1=-4
x=4-1 x=-4-1
x=3 x=-5
vậy.....
b/ 9x-1=1
=>x-1=0
x=1
vậy.....
Câu c làm như câu b
a) 5.(x+1)^2 = 80
=> (x+1)^2 = 16
=> \(\orbr{\begin{cases}x+1=4\\x+1=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-5\end{cases}}}\)
b) \(9^{x-1}=1\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
c) \(5^{x-2}=1\Rightarrow x-2=0\)
\(\Rightarrow x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^2-1=80\)
\(x^2=80+1\)
\(x^2=81\)
\(x^2=9^2\)
\(\Rightarrow x=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x-5\right)^2-1=80\)
\(\left(x-5\right)^2=80+1\)
\(\left(x-5\right)^2=81\)
\(\left(x-5\right)^2=9^2\)
\(\left(x-5\right)=9\)
\(x=9+5\)
\(x=14\)
Vậy ...
\(\left(x-5\right)^2-1=80\)
\(\left(x-5\right)^2=80+1\)\(=81\)
\(\left(x-5\right)^2=9^2\)
\(\left(x-5\right)=9\)
\(x=9+5=14\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$2^{x+1}+2^{x+1}=80$
$2.2^{x+1}=80$
$2^{x+2}=80$
Giá trị $x$ tìm được sẽ khá xấu. Bạn xem lại đề.