![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ x - ( 25 - x) = x - 15
=> x - 25 + x = x - 15
=> 2x - x = -15 + 25
=> x = 10
b/ x - 8 = -13 - 8
=> x = -13 - 8 + 8 = -13
c/ x - (-15) = 5 - (-19)
=> x + 15 = 5 + 19 => x = 5 + 19 - 15 = 9
d/ (x + 35) = 2x + 15 + (13 - 4)
=> x + 35 = 2x + 15 + 13 - 4
=> x - 2x = 15 + 13 - 4 - 35
=> -x = -11 => x = 11
e/ 5 - 2x = 15-(-9) - 3x
=> 5 - 2x = 15 + 9 - 3x
=> -2x + 3x = 15 + 9 - 5
=> x = 19
g/ x + 135 = 3x - 15
=> x - 3x = -15 - 135
=> -2x = -150
=> x = -150/ - 2 = 75
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 4x-(2x-5)=21
4x-2x+5=21
2x+5=21
2x=21 -5
2x=16
x=16/2
x=8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-15\right)\left(2x-6\right)=2x-6\)
\(\Leftrightarrow\left(3x-15\right)\left(2x-6\right)-\left(2x-6\right)=0\)
\(\Leftrightarrow\left(2x-6\right)\left(3x-16\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-6=0\\3x-16=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=\frac{16}{3}\end{cases}}\)
(3x-15).(2x-6)=2x-6
3x-15 =(2x-6):(2x-6)
3x-15 =1
3x =1+15
3x =16
x =16:3
x = 8
Vậy x =8
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x-2=6-5x-16
6x= -8
x= -4/3
b)-5x-(-3)-x=13-x
-5x+3-x=13-x
-5x=10
x=-2
c)15-(x-7)=-21-x
15-x+7=-21-x
22=-21 ( vô lí)
x không có giá trị
D)3x+17=2+3x+15
17=17
x có vô số giá trị
e) x-45-(x-9)=-35-x
x-45-x+9=-35-x
-x=1
x=-1
f) -5+x=15-x-2x
4x=20
x=5
g) 2x-(-17) =15
2x+17=15
2x=-2
x=-1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Leftrightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
+ \(2x-15=0\)\(\Leftrightarrow\)\(x=\frac{15}{2}\)
+\(\left(2x-15\right)^2-1=0\)\(\Leftrightarrow\)\(2x-15=\pm1\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=8\\x=7\end{cases}}\)
Vậy \(x\in\left\{\frac{15}{2};8;7\right\}\)
a, \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Leftrightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)
\(\Leftrightarrow\left(2x-15\right)^3\left(2x-16\right)\left(2x-14\right)=0\)
\(\Leftrightarrow x=\frac{15}{2};8;7\)
`2x + 3x = 15`
`x(2+3) =15`
`5x=15`
`x=15/5 =3`
`2x+3x=15`
`(2+3)x=15`
`5x=15`
`x=15:5=3`