Question

[Nguyễn Quang Huy]

(2x-3).(6-2x)=0

2.[1/2x-1/3]-3/2=1/4  (dấu[ ] là dấu giá trị tuyệt đối)

Answer 1

[ThuTrègg]

\(\left(2x-3\right)\left(6-2x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x-3=0\\6-2x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=3\end{cases}}}\)

Vậy ...

Answer 2

[ThuTrègg]

\(2.\left|\frac{1}{2}x-\frac{1}{3}\right|-\frac{3}{2}=\frac{1}{4}\)

\(\Leftrightarrow2.\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{7}{4}\)

\(\Leftrightarrow\left|\frac{1}{2}x-\frac{1}{3}\right|=\frac{7}{8}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{7}{8}\\\frac{1}{2}x-\frac{1}{3}=\frac{-7}{8}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{29}{12}\\x=\frac{-13}{12}\end{cases}}\)

Vậy..