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`Answer:`
a. \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{41}{4}+\frac{3}{4}\\2x=-\frac{41}{4}+\frac{3}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=11\\2x=-\frac{19}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=11:2\\x=-\frac{19}{2}:2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=-\frac{19}{4}\end{cases}}\)
b. \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)=\left(\frac{3}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}-\frac{1}{5}\\x=-\frac{3}{5}-\frac{1}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}\)
c. \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}-\left(-\frac{24}{27}\right)\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{7}{9}=-\frac{2}{3}\)
\(\Leftrightarrow3x=-\frac{2}{3}+\frac{7}{9}\)
\(\Leftrightarrow3x=\frac{1}{9}\)
\(\Leftrightarrow x=\frac{1}{9}:3\)
\(\Leftrightarrow x=\frac{1}{27}\)
\(2x-6=2\left(x-5\right)+25+27-15-17\)
\(\Leftrightarrow2x-6=3x-15+52-32\)
\(\Leftrightarrow2x=3x+37-32+6\)
\(\Leftrightarrow2x=3x+37-26\)
\(\Leftrightarrow2x=3x+11\text{( vô lí )}\)
\(\text{Vậy }x\in\varnothing\)
a) -2x - (x-17) = 34-(-x + 25)
-2x- x+17= 34+x-25
-2x-x-x= -17 +34-25
-4x = -8
x = 2
b)17x-(-16x-27) = 2x+43
17x + 16x + 27 = 2x + 43
17x + 16x -2x= -27 +43
31x= 26
x= 21/31
c)- 2x- 3(x-17) = 34- 2(-x + 25)
-2x - 3x + 51 = 34 + 2x -50
-2x - 3x -2x = -51 + 34 -50
-7x = -67
x = 67/7
d) 17x +3(-16x-37) = 2x+ 43 -4x
17x -48x -111 = 2x + 43 -4x
17x - 48x -2x + 4x = 111 -43
-29x = 68
x = -68/29
35-(x-7)=-7-(-27)+3x
=>35-x+7=-7+27+3x
=>-x+42=20+3x
=>3x-x=42-20
=>2x=22
=>x=11
\(\text{( 2x - 10 ) ( 3x + 27 ) = 0 }\)
\(\Rightarrow\orbr{\begin{cases}2x-10=0\\3x+27=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=0+10\\3x=0-27\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=10\\3x=-27\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=10:2\\x=\left(-27\right):3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-9\end{cases}}\)
vậy_____
-17 ( x + 10 ) > 0
=> -17 và x+10 cùng dấu
mà -17 mang dấu (-)
=> x+10 cũng mang dấu (-)
=> x < (-10)
=> x thuộc {-11;-12;-13;.....}
vậy_____
mấy câu này dễ, em chỉ cần nhắm vững lí thuyết là được
\(\left(2x-10\right)\left(3x+27\right)=0\)
\(2.\left(x-5\right).3.\left(x+9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+9=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-9\end{cases}}\)
vậy...
\(-17.\left(x+10\right)>0\)
\(\Rightarrow x+10< 0\) ( vì \(-17< 0\))
\(\Rightarrow x< -10\)
vậy \(x< -10\)
17 - 2x = -15
2x = 17 - (-15)
2x = 32
x = 32 : 2
x = 16
--------
54 : (x + 2) = -6
x + 2 = 54 : (-6)
x + 2 = -9
x = -9 - 2
x = -11
--------
12.(3 - x) = 72
3 - x = 72 : 12
3 - x = 6
x = 3 - 6
x = -3
-------
-3(x + 5) + 18 = -27
-3(x + 5) = -27 - 18
-3(x + 5) = -45
x + 5 = -45 : (-3)
x + 5 = 15
x = 15 - 5
x = 10
-------
(x + 5)² = 9
x + 5 = 3 hoặc x + 5 = -3
*) x + 5 = 3
x = 3 - 5
x = -2
*) x + 5 = -3
x = -3 - 5
x = -8
Vậy x = -8; x = -2
--------
(3 - x)³ = 27
(3 - x)³ = 3³
3 - x = 3
x = 3 - 3
x = 0
( 2x - 27 ) + 17 = x - 27
2x - 27 + 17 = x - 27
2x - x = 27 - 27 + 17
x = 17
=> 2x-27+17 = x-27
=> 2x-10 = x-27
=> 2x-10+27 = x
=> 2x+17 = x
=> x-2x = 17
=> -x = 17
=> x=-17
Vậy x=-17
Tk mk nha