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a)
\(3^4.3^n:9=3^7\)
\(\Rightarrow3^4.3^n=3^7.9\)
\(\Leftrightarrow3^4.3^n=3^7.3^2\)
\(\Rightarrow3^4.3^n=3^9\)
\(\Rightarrow3^n=3^9:3^4\)
\(\Rightarrow3^n=3^5\)
\(\Rightarrow n=5\)
Vậy \(n=5\)
d)
\(2^n:4=16\)
\(\Leftrightarrow2^n:2^2=2^4\)
\(\Rightarrow2^n=2^4.2^2\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
Vậy \(n=6\)
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2x.162 = 1024
=> 2x.(24)2 = 210
=> 2x + 4.2 = 10
=> x + 8 = 10
=> x = 2
vậy_
64.4x = 168
=> 43.4x = (42)8
=> 43 + x = 416
=> 3 + x = 16
=> x = 13
vậy_
2x = 16
=> 2x = 24
=> x = 4
vậy_
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a)2^n=128.16
2^n=2048
2^n=2^11
suy ra n=11
b)3^n=243.3^2
3^n=3^5.3^2
3^n=3^7
suy ra n=7
c)2^n:2^2=2^4
2^n=2^4.2^2
2^n=2^6
n=6
d)3^n=34:37
3^n=34/37
suy ra n ko có giá trị
e)9.81.3^n=310
3^n=310:9:81
3^n=310/729
suy ra n ko có giá trị
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\(2^n:4=16\Rightarrow2^n=64\Rightarrow2^n=2^6\Rightarrow n=6\)
\(3^n:3^2=243\Rightarrow3^n=2187\Rightarrow3^n=3^7\Rightarrow n=7\)
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ta có :
\(\hept{\begin{cases}4^{15}.9^{15}=36^{15}=6^{30}\\18^{16}.2^{16}=36^{16}=6^{32}\end{cases}}\) mà \(2^n.3^n=6^n\Rightarrow30< n< 32\Rightarrow n=31\)
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ta có:
2n=16
24=16 =>n=4
vậy n=4