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27 x (-53 ) + ( -27) x 47
= 27 x ( -53 + -47 )
= 27 x ( - 100 ) = -2700

\(\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}+\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}\)
\(=\left(\dfrac{3}{41}+\dfrac{4}{41}\right)-\left(\dfrac{12}{47}+\dfrac{16}{47}\right)+\left(\dfrac{27}{53}+\dfrac{36}{53}\right)\)
\(=\dfrac{7}{41}-\dfrac{28}{47}+\dfrac{63}{53}\)
\(=-\dfrac{819}{1927}+\dfrac{63}{53}\)
≃\(0,8\)

a) 27 x 35 + 73 x 6 - 27 x 29
= 27 x ( 35 - 29 ) + 73 x 6
= 27 x 6 + 73 x 6
= 6 x ( 27 + 73 )
= 6 x 100
= 600
b) 29 x ( 47 + 53 ) - 47 x ( 29 + 53 )
= 29 x 47 + 29 x 53 - 47 x 29 + 47 x 53
= 29 x ( 47 + 53 - 47 ) + 47 x 53
= 29 x 53 + 47 x 53
= 53 x ( 29 + 47 )
= 53 x 76
= 4028
c) 5 x 17 x 4 x 25 x 20
= ( 5 x 20 ) x ( 4 x 25 ) x 17
= 100 x 100 x 17
= 10000 x 17
= 170000

\(a.\left(47\times27\right)\times\left(-13\right)+13\left(-53-27\right)\)
\(=1269\times\left(-1\right)\times13+13\left(-80\right)\)
\(=13\left(-1269\right)+13\left(-80\right)\)
\(=13\left[\left(-1269\right)+\left(-80\right)\right]\)
\(=13\left(-1349\right)\)
\(=-17537\)
\(b.-17\left(13+5\right)-13\left(-17-2\right)\)
\(=13\left(-17\right)+5\left(-17\right)-13\left(-17\right)+13.2\)
\(=0-85+26\)
\(=-59\)

a) `123 - 27 + 27 + 13 - 123`
`= (123 - 123) + (27 - 27) + 13`
`= 0 + 0 + 13`
`= 13`
`---`
b) `175 + 25 + 13 + 15 - 175 - 25`
`= (175-175)+(25-25)+25+13`
`=0+0+25+13`
`=28`
`---`
c) \(53\times39+47\times39+53\times21+47\times21\)
\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)
\(=\left(100\times39\right)+\left(100\times21\right)\)
\(=3900+2100\)
`=6000`
`---`
d) \(49\times35+49\times16-49\times61\)
`=` \(49\times\left(35+16-61\right)\)
`=` \(49\times\left(-10\right)\)
`=-490`


Ta có: \(13\cdot\left(-47\right)-53\cdot13\)
\(=13\cdot\left(-47-53\right)\)
\(=13\cdot\left(-100\right)=-1300\)
Ta có: \(27\cdot\left(-67\right)+33\cdot\left(-27\right)\)
\(=27\cdot\left(-67\right)-33\cdot27\)
\(=27\left(-67-33\right)\)
\(=27\cdot\left(-100\right)=-2700\)
Ta có: \(-49\cdot65+36\cdot\left(-49\right)+49\)
\(=-49\cdot65+\left(-49\right)\cdot36+\left(-49\right)\cdot\left(-1\right)\)
\(=-49\cdot\left(65+36-1\right)\)
\(=-49\cdot100=-4900\)
Ta có: \(136\cdot\left(-47\right)+36\cdot47\)
\(=\left(-136\right)\cdot47+36\cdot47\)
\(=47\cdot\left(-136+36\right)\)
\(=47\cdot\left(-100\right)=-4700\)
Ta có: \(\left(-48\right)\cdot72+36\cdot\left(-304\right)\)
\(=-96\cdot36+36\cdot\left(-304\right)\)
\(=36\cdot\left(-96-304\right)\)
\(=36\cdot\left(-400\right)=-14400\)

\(\frac{\frac{3}{41}-\frac{12}{47}+\frac{27}{53}}{\frac{4}{41}-\frac{16}{47}+\frac{36}{53}}=\frac{3\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)
\(\frac{\frac{3}{41}-\frac{12}{47}+\frac{27}{53}}{\frac{4}{41}-\frac{16}{47}+\frac{36}{53}}=\frac{3\cdot\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4\cdot\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)
Chúc bạn học tốt!^_^

\(\frac{\frac{3}{41}-\frac{12}{47}+\frac{27}{53}}{\frac{4}{41}-\frac{16}{47}+\frac{36}{53}}=\frac{3.\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4.\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)

\(=\frac{3.\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}{4.\left(\frac{1}{41}-\frac{4}{47}+\frac{9}{53}\right)}=\frac{3}{4}\)
\(=27.[-53+\left(-47\right)] \)]
\(=27.\left(-100\right)\)
\(=-2700\)
T ick cho anh nha