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\(x+\left(x+1\right)+\left(x+2\right)+....+13+14=14\Leftrightarrow x+\left(x+1\right)+....+13\Leftrightarrow x=-13\)
\(25+24+23+....+x+\left(x-1\right)+\left(x-2\right)=25\Leftrightarrow24+....+\left(x-2\right)=0\Leftrightarrow x-2=-24\)
\(\Leftrightarrow x=-22\)
a, (x2 + 5)(x2 - 25) = 0
\(\Rightarrow\left[\begin{matrix}x^2+5=0\\x^2+25=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}x^2=-5\left(loại\right)\\x^2=-25\left(loại\right)\end{matrix}\right.\)
Vậy \(x=\varnothing\)
b, (x2 - 5)(x2 - 25) < 0
<=> x2 - 5 và x2 - 25 trái dấu
Ta thấy x2 - 5 > x2 - 25 nên \(\left\{\begin{matrix}x^2-5>0\\x^2-25< 0\end{matrix}\right.\) <=> x < 5
c, (x - 2)(x + 1) = 0
\(\Rightarrow\left[\begin{matrix}x-2=0\\x+1=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
Vậy \(x\in\left\{2;-1\right\}\)
a: =>14x+2*(14*13/2)=14
=>14x+14*13=14
=>14x=-12*14
=>x=-12
b: =>3x+(0-1-2-3+1+2+...+25)=25
=>3x+4+...+25=25
=>3x+4+...+24=0
=>3x+(24-4+1)*28/2=0
=>3x+21*28/2=0
=>3x=-21*14
=>x=-7*14=-98
Tìm x biết
a) (x-1/2)^2=4
b) 10/1/2-(x+1/3)^2=1/1/2
c) (x-1/5)^2+17/25=26/25
d) 1/5/27+(3x-7/9)^3=24/27
a) (x - 1/2)2 = 4
<=> (x - 1/2)2 = 22
<=> x - 1/2 = -2; 2
<=> x - 1/2 = 2 hoặc x - 1/2 = -2
x = 2 + 1/2 x = -2 + 1/2
x = 5/2 x = -3/2
=> x = 5/2 hoặc x = -3/2
b) 10/1/2 - (x + 1/3)2 = 1/1/2
<=> -(x + 1/3)2 = 1/1/2 - 10/1/2
<=> -(x + 1/3)2 = 1/2 - 5
<=> -(x + 1/3)2 = -5.2 + 1/2
<=> -(x + 1/3)2 = -9/2
<=> (x + 1/3)2 = 9/2
<=> x + 1/3 = \(\sqrt{\frac{9}{2}}\) hoặc x + 1/3 = \(-\sqrt{\frac{9}{2}}\)
x = \(\frac{3\sqrt{2}}{2}\) - 1/3 x = \(-\frac{3\sqrt{2}}{2}\) -1/3
=> x = \(\frac{3\sqrt{2}}{2}\) - 1/3 hoặc x = \(-\frac{3\sqrt{2}}{2}\) -1/3
c) (x - 1/5)2 + 17/25 = 26/25
<=> (x - 1/5)2 = 26/25 - 17/25
<=> (x - 1/5)2 = (3/5)2
<=> x - 1/5 = -3/5; 3/5
<=> x - 1/5 = 3/5 hoặc x - 1/5 = -3/5
x = 3/5 + 1/5 x = -3/5 + 1/5
x = 4/5 x = -2/5
=> x = 4/5 hoặc x = -2/5
1. 11(x-9)=77
x-9=7
x=16
2. 4(x-3)=48
x-3=12
x=15
3.3(x-8)=81
(x-8)=27
x=35
a)\(\frac{x}{150}\)=\(\frac{5}{6}\).\(\frac{-7}{25}\)
⇒\(\frac{x}{150}\)=\(\frac{-7}{30}\)
⇒30x=-7.150
⇒x=\(\frac{-1050}{30}\)=-35
vậy x=-35
b)\(\frac{1}{2}\).x+\(\frac{3}{5}.x\)\(=3\)
⇒\(\frac{11}{10}x=3\)
\(\Rightarrow x=\frac{30}{11}\)
Vậy x=\(\frac{30}{11}\)
c)\(25\%.x+x=2\frac{1}{2}\)
\(\Rightarrow\frac{1}{4}.x+x=\frac{5}{2}\)
⇒\(\frac{5}{4}x=\frac{5}{2}\)
⇒\(x=2\)
Vậy\(x=2\)
d)\(\left|2x\right|=15\)
\(\Rightarrow\left[{}\begin{matrix}2x=15\\2x=-15\end{matrix}\right.\)
⇒\(\left[{}\begin{matrix}x=\frac{15}{2}\\x=-\frac{15}{2}\end{matrix}\right.\)
Vậy \(x=\frac{15}{2}\)hoặc \(x=\frac{-15}{2}\)
//học tốt//
\(25\%.x+x=-2\frac{1}{2}\)
\(\frac{1}{4}.x+x=-2\frac{1}{2}\)
\(x.\left(\frac{1}{4}+1\right)=-2\frac{1}{2}\)
\(x.\frac{5}{4}=\frac{-5}{2}\)
\(x=\frac{-5}{2}\div\frac{5}{4}\)
\(x=-2\)(đã thu gọn)
1/4.x+x=-5/2
(1/4+1).x=-5/2
5/4.x=-5/2
x=-5/2:5/4
x=-5/2.4/5
x=-2