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a)\(\frac{2}{3}:\frac{4}{9}+\frac{1}{3}:\frac{4}{9}\)
=\(\frac{4}{9}:\left(\frac{2}{3}+\frac{1}{3}\right)\)
=\(\frac{4}{9}:1=\frac{4}{9}\)
b
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Các phân số sắp xếp theo thứ tự từ bé đến lớn là: 5/12; 2/3; 3/4; 5/6.
Hok tốt.
2/3, 5/6, 3/4, 5/12 quy đồng ra = 8/12, 10/12, 9/12 và 5/12 giữ nguyên
Sắp xếp theo thứ tự từ bé - lớn là : 5/12; 2/3; 3/4; 5/6
Mình hơi hậu đậu nếu có gì sai thì thông cảm nhé :33
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Gọi số cần tìm là x, ta có
5/7<x<6/7
-> 35/49<x<42/49
vậy x là : 36/49 , 37/49 , 38/49 , 39/48 , 40/49 , 41/49
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a) \(\frac{6}{5}\)- \(\frac{2}{3}\)= \(\frac{18}{15}\)- \(\frac{10}{15}\)= \(\frac{8}{15}\)
b) 1 - \(\frac{4}{5}\)= \(\frac{5}{5}\)- \(\frac{4}{5}\)= \(\frac{1}{5}\)
c) \(\frac{5}{12}\)- \(\frac{1}{4}\)= \(\frac{5}{12}\)- \(\frac{3}{12}\)= \(\frac{2}{12}\)= \(\frac{1}{6}\)
d) \(\frac{7}{8}\) - \(\frac{1}{6}\) = \(\frac{21}{24}\) - \(\frac{4}{24}\)= \(\frac{17}{24}\)
~HT~
a) 6/5 - 2/3 = 8/15
b) 1 - 4/5 = 1/5
c) 5/12 - 1/4 = 1/6
d) 7/8 - 1/6 = 17/24
HT~
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ta thay day so tren la day so tu nhien lien tiep bat dau tu 1 va ket thuc la 100 nen co 100 so hang
tong la (100+1) x 100 :2=5050
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Tính nhanh mỗi biểu thức sau:
a, 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20
= (0 + 20) + (1 + 19) + (2 + 18) + (3 + 17) + (4 + 16) + (5 + 15) + (6 + 14) + (7 + 13) + (8 + 12) + (9 + 11) + 10
= 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 10
= 20 x 10 + 10
= 200 + 10
= 210
b, 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (4 x 9 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x (36 - 36)
= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 0
= A x 0
= 0
c, (81 - 7 x 9 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (81 - 63 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= (18 - 18) : (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 :(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9)
= 0 : A
= 0
d, (6 x 5 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (30 + 7 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (37 - 37) x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x A
= 0
e, (11 x 9 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 - 100 + 1) : (1 x 2 x 3 x 4 x ... x 10)
= (99 + 1 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= (100 - 100) : (1 x 2 x 3 x 4 x ... x 10)
= 0 : (1 x 2 x 3 x 4 x ... x 10)
= 0 : A
= 0
g, (m : 1 - m x 1) : (m x 2008 + m x 2008)
= (m - m) : (m x 2008 + m x 2008)
= 0 : (m x 2008 + m x 2008)
= 0 : A
= 0
h, (2 + 4 + 6 + 8 + m x n) x (324 x 3 - 972)
= (2 + 4 + 6 + 8 + m x n) x (972 - 972)
= (2 + 4 + 6 + 8 + m x n) x 0
= A x 0
= 0
l, (1 + 2 + 3 + ... + 99) x (13 x 15 - 12 x 15 - 15)
= (1 + 2 + 3 + ... + 99) x (15 x (13 - 12 - 1))
= (1 + 2 + 3 + ... + 99) x (15 x 0)
= (1 + 2 + 3 + ... + 99) x 0
= A x 0
= 0
i, (0 x 1 x 2 x...x 99 x 100) : (2 + 4 + 6 +...+ 98)
= 0 x : (2 + 4 + 6 +...+ 98)
= 0 x A
= 0
k, (0 + 1 + 2 +...+ 97 + 99) x (45 x 3 - 45 x 2 - 45)
= (0 + 1 + 2 +...+ 97 + 99) x (45 x (3 - 2 - 4))
= (0 + 1 + 2 +...+ 97 + 99) x (45 x 0)
= (0 + 1 + 2 +...+ 97 + 99) x 0
= A x 0
= 0
\(\frac{2}{5}+\frac{7}{12}+\frac{1}{9}+\frac{19}{8}+\frac{17}{9}+\frac{5}{12}+\frac{5}{8}\)
\(=\frac{2}{5}+\left(\frac{7}{12}+\frac{5}{12}\right)+\left(\frac{1}{9}+\frac{17}{9}\right)+\left(\frac{19}{8}+\frac{5}{8}\right)\)
\(=\frac{2}{5}+1+2+3\)
\(=\frac{2}{5}+6\)
\(=\frac{32}{5}\)