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Ta có: 10 - 2x = 25 - 3x
<=> 10 - 2x - 25 + 3x = 0
<=> x - 15 = 0
=> x = 15
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10 - 2x = 25 - 3x
10 - 25 = 2x - 3x
-15 = -x
=> x = 15
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10-2x=25-3x
=>2x+3x=25-10
=>x(2+3)=15
=>5x=15
=>x=15:5
=>x=3
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25-{14-[(2-x)-(x+13)+23]}=62-{8-[(2x-10)-(29-3x)+8]}
<=>25-14+2-x-x-13+23=62-8+2x-10-29+3x+8
<=>13-x-x-13+23=2x+3x+8-10-29
<=>-x-x+23=2x+3x+(-31)
<=>23-(x+x)=2x+2x-31
<=>23-2x=2x+3x-31
<=>23+31=2x+2x+3x
<=>54=x(2+2+3)
<=>54=x.7
=>x=54/7
Vậy x=54/7
<=>54=x.7
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a) x - (17 - 8) = 5 + (10 - 3x)
x - 17 + 8 = 5 + 10 - 3x
x + 3x = 5 + 10 + 17 - 8
4x = 24
x = 24 : 4
x = 6
b) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = (-14) : (-2)
x = 7
c) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 -18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
d) 9 - 25 = (7 - x) - (25 + 7)
9 - 25 = 7 - x - 25 - 7
x = 7 - 25 - 7 - 9 +25
x = -9
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( 3x - 1 )3 = 125
( 3x - 1 )3 = 53
=> 3x - 1 = 5
3x = 6
x = 2
( 10 + x ) : 25 = 30 . 22
( 10 + x ) : 25 = 4
10 + x = 100
x = 90
25 - 3x = 10
3x = 25 - 10
3x = 15
x = 15 : 3
x = 5
\(25-3x=10\)
\(3x=25-10\)
\(3x=15\)
\(x=15:3\)
\(x=5\)