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\(\frac{2}{3}\times\frac{4}{5}+\frac{1}{3}\times\frac{4}{5}\)
\(=\left(\frac{2}{3}+\frac{1}{3}\right)\times\frac{4}{5}\)
\(=1\times\frac{4}{5}\)
\(=\frac{4}{5}\)
2/3 x 4/5 + 1/3 x 4/5
= 4/5 x (2/3 + 1/3 )
= 4/5 x 1
= 4/5
mong các bạn nha
\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{9\cdot10}\right)\cdot100-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=89\)
\(\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\cdot100-\left[\frac{5}{2}:\left(x+\frac{103}{50}\right)\right]\cdot2=89\)
\(\left(1-\frac{1}{10}\right)\cdot100-\frac{5}{2}:\left(x+\frac{103}{50}\right)\cdot2=89\)
\(\frac{9}{10}\cdot100-\frac{5}{2}\cdot2:\left(x+\frac{103}{50}\right)=89\)
\(90-5\cdot\left(x+\frac{103}{50}\right)=89\)
\(5\cdot\left(x+\frac{103}{50}\right)=1\)
\(x+\frac{103}{50}=\frac{1}{5}\)
\(x=-\frac{93}{50}\)
Ta có 1/3x4= 1/3- 1/4
2/4x6= 1/4-1/6
..............................
5/13x18= 1/13 - 1/18
=> 1/3 -1/4 + 1/4 -1/6 +......+ 1/13 -1/18
= 1/3 - 1/18
= 5/18
\(\frac{2}{3}\times\frac{4}{5}-\frac{1}{3}\times\frac{4}{5}\)
\(=\frac{8}{15}-\frac{4}{15}\)
\(=\frac{4}{15}\)
k mk nha mấy bạn
= 4/5 x (2/3 - 1/3 )
= 4/5 x 1/3
= 4/15