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a.8x+28-9x+6=24
<=> -x+34=24
<=> -x=24-34
<=> x=10
b. 3-6x-x-18=7
<=> -7x=7+18-3
<=> -7x=22
<=> x=22/-7
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Bạn rút gọn chéo đi 2 với 2 ,3 với 3 cứ như thế còn mỗi 1/100. k nhé
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Ta có: \(A=1-2+3-4+5-6+7-8+9\)
\(=(1+9)-(2+8)+(3+7)-(4+6)+5\)
\(=10-10+10-10+5\)
\(=5\)
Vậy \(A=5\)
B = 12 - 14 + 16 - 18 + ... + 2008 - 2010
B = -2 + (-2)+ (-2)+ (-2) + ...+ (-2)
B = -2 . 100
B = -200
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a, => 9 = 5.x - 3.x = 2.x
=> x = 9 :2 = 4,5
b, => 4 = x + x + 16
=> 4 = 2x+16
=> 2x = 4 - 16 = -12
=> x = -12 : 2 = -6
Tk mk nha
5x - 9 = 3x \(\Rightarrow\)5x - 3x = 9 \(\Rightarrow\)2x = 9 \(\Rightarrow\)\(x=\frac{9}{2}\)
4 - ( 16 + x ) = x \(\Rightarrow\)4 - 16 - x = x \(\Rightarrow\)2x = -12 \(\Rightarrow\)x = -6
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{-3}{16}+\frac{-7}{16}+\frac{6}{-16}\)
\(=-\frac{3}{16}+-\frac{7}{16}+\frac{-6}{16}\)
\(=\frac{\left(-3\right)+\left(-7\right)+\left(-6\right)}{16}\)
\(=\frac{-16}{16}=-1\)
b) \(\frac{2}{5}-\frac{1}{7}+\frac{7}{10}\)
\(=\frac{28}{70}-\frac{10}{70}+\frac{49}{70}\)
\(=\frac{28-10+49}{70}\)
\(=\frac{67}{70}\)
c) \(3+\frac{1}{3}-2\frac{1}{2}\)
\(=\frac{3}{1}+\frac{1}{3}-\frac{5}{2}\)
\(=\frac{18}{6}+\frac{2}{6}-\frac{15}{6}\)
\(=\frac{18+2-15}{6}\)
\(=\frac{5}{6}\)
d) \(-\frac{3}{5}-\left(-\frac{2}{15}\right)\)
\(=-\frac{3}{5}+\frac{2}{15}\)
\(=\frac{-9}{15}+\frac{2}{15}\)
\(=-\frac{7}{15}\)
\(\frac{-3}{16}\)+(\(\frac{-7}{16}\) ) +(\(\frac{6}{-16}\))
=\(\frac{-3-7-6}{16}\)
=\(\frac{-16}{16}\)= \(-1\)
\(\frac{2}{5}\)\(-\)\(\frac{1}{7}\)+\(\frac{7}{10}\)
=\(\frac{9}{35}\)+\(\frac{7}{10}\)
=\(\frac{67}{70}\)
3+ \(\frac{1}{3}\)\(-\) \(\frac{21}{2}\)
=\(\frac{18+2-63}{6}\)
=\(\frac{-43}{6}\)
\(\frac{-3}{5}\)\(-\)(\(\frac{-2}{15}\))
=\(\frac{-3}{5}\)+\(\frac{2}{15}\)
=\(\frac{-9+2}{15}\)
=\(\frac{-7}{15}\)
\(\left(-2\right)^3\cdot4+3\cdot\left(-16\right)-18\)
\(=\left(-8\right)\cdot4+\left(-48\right)-18\)
\(=\left(-32\right)+\left(-66\right)\)
\(=-98\)
(-2)3.4+3.(-16)-18
= (-8).4+3.(-16)-18
= -32-48-18
= -98