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1 tháng 2 2022
a: \(=\left(1.25\right)^{16}\cdot8^{16}\cdot8=8\cdot10^{16}\)
b: \(=\left(\dfrac{5}{2}\right)^{13}\cdot4^{13}\cdot4^2=10^{13}\cdot4^2\)
c: \(=\left(0.25\right)^4\cdot8^4\cdot8^2=2^4\cdot8^2=64\cdot16=1024\)
d: \(=\left(\dfrac{1}{2}\right)^{15}\cdot2^{18}=2^3=8\)
e: \(=\left(\dfrac{1}{3}\cdot6\right)^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=2^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=\dfrac{1}{2}\)
12 tháng 12 2018
\(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
\(=-8.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
\(=-8.\frac{1}{2}:\left(\frac{54}{24}-\frac{28}{24}\right)\)
\(=-4:\frac{13}{12}\)
\(=-4.\frac{13}{12}\)
\(=\frac{-13}{3}\)
12 tháng 12 2018
\((-2)^3\cdot(\frac{3}{4}-0,25):(2\frac{1}{4}-1\frac{1}{6})\)
\(=-8\cdot(0,75-0,25):(\frac{9}{4}-\frac{7}{6})\)
\(=-8\cdot0,5:\frac{13}{12}\)
\(=-8\cdot0,5\cdot\frac{12}{13}\)
\(=-4\cdot\frac{12}{13}=-\frac{48}{13}=-3\frac{9}{13}\)
\(=2\frac{4}{13}\)
\(\text{Bài toán này .... tính mất công }:)\text{ Bạn dùng máy tính thử kiểm tra có đúng không ?}\)
24 tháng 6 2018
a/ S = ( - 2/3 + 1) - (7/5 - 0,2) + )7/15 - 1 + 4/3) = - 2/3 + 1 - 7/5 + 1/5 +7/15 - 1 + 4/3 = 2/3 - 6/5 + 7/15 = 10/15 - 18/15 + 7/15 = - 1/15.
b/ S = 0,25 - 9- (- 3/4) - [ - 7/3 + (-9/2)] - 5/6 = 1/4 - 9 + 3/4 + 7/3 + 9/2 - 5/6 = - 8 + 14/6 + 27/6 - 5/6 = - 8 + 6 = - 2
DK
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IA
31 tháng 10 2020
\(a,\frac{1}{3}x+0.25=\frac{5}{7}\)
\(\Leftrightarrow\frac{1}{3}x=\frac{13}{28}\)
\(\Leftrightarrow x=\frac{39}{28}\)
vậy...
\(b,\frac{11}{12}x+0,25=\frac{5}{6}\)
\(\Leftrightarrow\frac{11}{12}x=\frac{7}{12}\)
\(\Leftrightarrow x=\frac{7}{11}\)
vậy.....
\(c,\left(\frac{-1}{3}\right)^2+\frac{2}{3}x=\frac{1}{4}\)
\(\Leftrightarrow\frac{1}{9}+\frac{2}{3}x=\frac{1}{4}\)
\(\Leftrightarrow\frac{2}{3}x=\frac{5}{36}\)
\(\Leftrightarrow x=\frac{5}{24}\)
vậy......
\(d,\left(3x+2\right)^3=-\frac{8}{125}\)
\(\Leftrightarrow3x+2=-\frac{2}{5}\)
\(\Leftrightarrow3x=-\frac{12}{5}\)
\(\Leftrightarrow x=-\frac{4}{5}\)
vậy.......
31 tháng 10 2020
\(\frac{1}{3x}+0,25=\frac{5}{7}\)
\(\frac{1}{3x}+\frac{1}{4}=\frac{5}{7}\)
\(\frac{1}{3x}=\frac{13}{28}\)
\(3x=\frac{28}{13}\)
\(x=\frac{28}{39}\)
\(\frac{11}{12x}+0,25=\frac{5}{6}\)
\(\frac{11}{12x}+\frac{1}{4}=\frac{5}{6}\)
\(\frac{11}{12x}=\frac{7}{12}\)
\(x=\frac{11}{12}:\frac{7}{12}\)
\(x=\frac{7}{11}\)
\(\left(-\frac{1}{3}\right)^2+\frac{2}{3x}=\frac{1}{4}\)
\(\frac{1}{9}+\frac{2}{3x}=\frac{1}{4}\)
\(\frac{2}{3x}=\frac{5}{36}\)
\(x=\frac{2}{3}:\frac{5}{36}\)
\(x=\frac{5}{24}\)
\(\left(3x+2\right)^3=\left(-\frac{8}{125}\right)\)
\(\left(3x+2\right)^3=\left(-\frac{2}{5}\right)^3\)
\(\Rightarrow3x+2=-\frac{2}{3}\)
\(3x=-\frac{8}{3}\)
\(x=-\frac{9}{8}\)
NN
9 tháng 12 2017
\(\left(-2\right)^3.\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-8.\left(\dfrac{3}{4}-\dfrac{1}{4}\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-8.\dfrac{3-1}{4}:\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-8.\dfrac{2}{4}:\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-8.\dfrac{1}{2}:\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-4:\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=-4:\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)
\(=-4:\left(\dfrac{27}{12}-\dfrac{14}{12}\right)\)
\(=-4:\dfrac{27-14}{12}\)
\(=-4:\dfrac{13}{12}\)
\(=-4.\dfrac{12}{13}\)
\(=\dfrac{-48}{13}\)
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