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720 : [ 41 - (2\(x\) - 5)] = 22.5
41 - (2\(x\) - 5) = 720 :110
2\(x\) - 5 = 41 - \(\dfrac{72}{11}\)
2\(x\) - 5 = \(\dfrac{379}{11}\)
2\(x\) = \(\dfrac{379}{11}\) + 5
2\(x\) = \(\dfrac{434}{11}\)
\(x\) = \(\dfrac{434}{11}\) : 2
\(x\) = \(\dfrac{217}{11}\)
15 - \(x\) = 7 - (-2)
15 - \(x\) = 7 + 2
15 - \(x\) = 9
\(x\) = 15 - 9
\(x\) = 6
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a) \(\left[136+\left(18-x\right).5\right].11^6=11^7\)
\(\Rightarrow\left[136+\left(18-x\right).5\right]=11\)
\(\Rightarrow\left(18-x\right).5=11-136=-125\)
\(\Rightarrow18-x=-125:5=-25\)
\(\Rightarrow x=18-\left(-25\right)=18+25=43\)
b) \(x\in B\left(15\right);362< x\le390\)
\(\Rightarrow x\in\left\{375;390\right\}\)
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\(=15:\left\{390:\left[125\cdot4-5\cdot32-210\right]\right\}\)
\(=15:\left\{390:130\right\}=15:3=5\)
=> 15:{390:[125.4-(5.32+210)]}
=> 15:{390:[500-(160+210)]}
=> 15:{390:[500-370]}
=> 15:{390:130}
=> 15:3=5
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=15 : { 390 : [ 125.4 - ( 5.32 + 35 . 6 ) ] }
=15 : { 390 : [ 500 - ( 160 + 35 . 6 ) ] }
=15 : { 390 : [ 500 - ( 160 + 210 ) ] }
=15 : { 390 : [ 500 - 370 ] }
=15 : { 390 : 130 }
= 15: 3
= 5
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390-(x-7)=169:13
390-(x-7)=13
X-7=390-13
X-7=377
X=377+7
X=384
phần a bạn ở dưới làm r nhé
phần b chép sai đề
phần c :
x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0
<=>x - 3 - 24 : 12 - 3 = 0
<=>x - 3 - 2 - 3 = 0
<=>x=8
Vậy x = 8
phần d :
x + 5 . 2 - ( 32 + 16 . 3 : 16 - 15 ) = 0
<=>x + 10 - ( 32 + 3 - 15 ) = 0
<=> x + 10 - 20 = 0
<=>x = 10
Vậy x = 10
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hình như bài làm r bạn ạ :0 mình giải r đấy xem lại nhé :V
a) \(390-\left(x-7\right)=169:13\)
\(390-\left(x-7\right)=13\)
\(x-7=390-13\)
\(x-7=377\)
\(x=384\)
b) \(\left(x-110\right):7-3^3-2^3.3\)
Đề sai nhé bạn
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-\left(24\right):2:6=3\)
\(x-3-\left(24\right):2=18\)
\(x-3-\left(24\right)=36\)
\(x-3=36+24\)
\(x-3=60\)
\(x=63\)
d) \(x+5.2-\left(32+16.3:16-15\right)=0\)
\(x+10-\left(32+48:16-15\right)=0\)
\(x+10-\left(32+3-15\right)=0\)
\(x+10-20=0\)
\(x+10=20\)
\(x=10\)
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15*(32-24:x)-230=70
15*(32-24:x)=70+230
15*(32-24:x)=300
32-24:x=300:15
32-24:x=20
24:x=32-20
24:x=12
x=24:12
x=2