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A= 82 . 324 = (23)2 . (25)4 = 26.220 = 226
\(B=27^3.9^4.81^2\)
\(=\left(3^3\right)^3.\left(3^2\right)^4.\left(3^4\right)^2\)
\(=3^9.3^8.3^8\)
\(=3^{25}\)
A) \(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}\)
do \(8^{100}< 9^{100}=>A< B\)
B) \(27^5=\left(3^3\right)^5=3^{15}\)
\(243^3=\left(3^5\right)^3=3^{15}\)
=> \(27^5=243^3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A=1+3+32+33+....+370
3A=3+32+33+34+...+371
3A—A=(3+32+33+34+...+371)—(1+3+32+33+...+370)
2A=371—1
A=(371—1):2
Còn lại tự làm...
cảm ơn bạn nhé
bạn cố gắng suy nghĩ để trả lời mấy ý còn lại cho mình nha , mình cảm ơn
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\(A,\frac{4^9.36+64}{16^4.100}=\frac{\left(2^2\right)^9.2^2.3^2+2^6}{\left(2^4\right)^4.2^2.5^2}=\frac{2^{20}.3^2+2^6}{2^{18}.5^2}=\frac{2^6\left(2^{14}.3^2+1\right)}{2^{18}.5^2}=\frac{2^{14}.3^2+1}{2^{12}.5^2}=\frac{147457}{102400}\)
B,
\(\frac{11.3^{22}.3-9^{13}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22}-\left(3^2\right)^{13}}{2^2.3^{28}}=\frac{11.3^{22}-3^{26}}{2^2.3^{28}}=\frac{3^{22}\left(11.1-3^4\right)}{2^2.3^{28}}=\frac{11-81}{2^2.3^6}=-\frac{70}{2916}=-\frac{35}{1456}\)
c,
\(\frac{45^3.20^4.18}{180^5}=\frac{\left(3^2.5\right)^3.\left(5.2^2\right)^4.2.3^2}{\left(2^2.3^2.5\right)^5}=\frac{3^6.5^3.5^4.2^8.2.3^2}{2^{10}.3^{10}.5^5}=\frac{3^8.2^{10}.5^7}{2^{10}.3^{10}.5^5}=\frac{5^2}{3^2}=\frac{25}{9}\)
\(\frac{4^9\cdot36+64}{16^4\cdot100}=\frac{2^6\cdot147457}{2^{16}\cdot100}=\frac{147457}{2^{10}\cdot100}\)
\(\frac{11\cdot3^{22}\cdot3-9^{13}}{2^2\cdot3^{28}}=\frac{3^{23}\left(11-3^3\right)}{2^2\cdot3^{28}}=\frac{-16\cdot3^{23}}{2^2\cdot3^{28}}=\frac{-4}{243}\)
\(\frac{45^3\cdot20^4\cdot18}{180^5}=\frac{3^8\cdot2^9\cdot5^7}{2^{10}\cdot3^{10}\cdot5^5}=\frac{25}{18}\)
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2^2 = 2.2 = 4
2^3 = 2.2.2 = 8
2^4 = 2.2.2.2. = 16
2^5 = 2.2.2.2.2 = 32
2^6 = 2.2.2.2.2.2 = 64
2^7 = 2.2.2.2.2.2.2 = 128
2^8 = 2.2.2.2.2.2.2.2 = 256
2^9 = 2.2.2.2.2.2.2.2.2 = 512
3^2 = 3.3 = 9
3^3 = 3.3.3 = 27
3^4 = 3.3.3.3 = 81
3^5 = 3.3.3.3.3 = 243
=> mình giải giúp bạn hai bài trên rồi nhé, cứ thế rồi bạn làm mấy bài tiếp theo chứ mà giải nữa thì lâu lắm với bài cũng dễ :>
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a) 52x+1=125
=>52x+1= 53
=>2x+1=3
=>2x = 2
=>x =1
c)73<x <=93
=>343<x<=729
=> x = { 344;345;...;729}
d) (2x+3)4=81
=>(2x+3)4=34
=>2x+3 =3
=>2x =0
=> x = 0
nhớ tk nha
a)52x+1=125
52x+1=53
⏩ 2x+1=3
2x=4
x=4:2
x=2
b) (2x)2(2x) 3 =25.25
(2x) 2 (2x) 3 =210
(2x) 5=1024
(2x) 5 =45
2x=4
x=4 :2=2
d)(2x +3)4=81
(2x +3)4=34
2x+3=3
2x=0
x=0
Câu c bạn tự giải nhé
Nhớ tk giùm mình đấy
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a)\(\left(10^2+11^2+12^2\right)\div\left(13^2+14^2\right)\)
\(=\left(100+121+144\right)\div\left(169+196\right)\)
\(=365\div365\)
\(=1\)
b) \(1.2.3...9-1.2.3...8-1.2.3...8^2\)
\(=1.2.3...8\left(9-1-8\right)\)
\(=1.2.3...8.0\)
\(=0\)
d) \(1152-\left(374+1152\right)+\left(-65+374\right)\)
\(=1152-374-1152-65+374\)
\(=\left(1152-1152\right)-65+\left(374-374\right)\)
\(=0-65+0\)
\(=-65\)
e) \(13-12+11+10-9+8-7-6+5-4+3+2-1\)
\(=13-\left(12-11\right)+\left(10-9\right)+\left(8-7\right)-\left(6-5\right)-\left(4-3\right)\)\(+\left(2-1\right)\)
\(=13-1+1+1-1-1+1\)
\(=13+0+0+0\)
\(=13\)
\(\left(2^2\cdot|x|-5^2\right)\cdot3^8=3^9\)
\(\left(2^2\cdot\left|x\right|-5^2\right)=3^9:3^8\)
\(4\cdot\left|x\right|-25=3\)
\(4\cdot\left|x\right|=3+25\)
\(4\cdot\left|x\right|=28\)
\(\Rightarrow\left|x\right|=28:4\)
\(\left|x\right|=7\)
\(\Rightarrow\hept{\begin{cases}x=-7\\x=7\end{cases}}\)
_Pé Nguyên's_ làm đúng rồi