![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{2^{15}\cdot9^4}{6^8\cdot8^3}=\dfrac{2^{15}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^8\cdot\left(2^3\right)^3}=\dfrac{2^{15}\cdot3^8}{2^8\cdot3^8\cdot2^9}=\dfrac{2^{15}\cdot3^8}{2^{17}\cdot3^8}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
\(\dfrac{2^{15}.9^4}{6^8.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^8.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^8.3^8.2^9}=\dfrac{2^{15}}{2^{17}}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}\)
\(=\frac{\left(2.3\right)^{15}.3^{20}}{3^{34}.2^{13}}\)
\(=\frac{2^{15}.3^{25}}{3^{34}.2^{13}}\)
\(=\frac{2^2.3}{1.1}=2^2.3=12\)
\(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}=\frac{2^{15}.3^{15}.3^{20}}{3^{34}.2^{13}}=\frac{2^{15}.3^{35}}{3^{34}.2^{13}}=2^2.3=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: =>5x-1=0 hoặc 2x-1/3=0
=>x=1/6 hoặc x=1/5
b: =>x-1=4
=>x=5
c: \(\Leftrightarrow3^4< \dfrac{1}{3^2}\cdot3^{3x}< 3^{10}\)
=>4<3x-2<10
=>\(3x-2\in\left\{5;6;7;8;9\right\}\)
hay \(x=3\)
2^15 . 9^4/6^8 . 8^3
2^15 . (3^2)^4 / 2^8.3^8 . (2^3)^3
2^15. 3^8 / 2^8 . 3^8 . 2^9
2^15 . 3^8 / 2^15 . 3^8
suy ra : (2^15 . 3^8) :( 2^15 . 3^8) = 1