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\(\frac{20^5.5^{10}}{100^5}=\frac{20^5.25^5}{100^5}=\frac{\left(20.25\right)^5}{100^5}=\frac{500^5}{100^5}=5^5\)
\(\frac{20^5.5^{10}}{100^5}=\frac{20^5.\left(5^2\right)^5}{100^5}=\frac{20^5.25^5}{100^5}=\frac{\left(20.25\right)^5}{100^5}=\frac{500^5}{100^5}=\frac{\left(100.5\right)^5}{100^5}=\frac{100^5.5^5}{100^5}=5^5=3125\)
a: \(=\dfrac{5^5\cdot5^{10}\cdot4^5}{5^{10}\cdot2^{10}}=5^5\)
b: \(=\left(\dfrac{0.9}{0.3}\right)^5\cdot\dfrac{1}{0.3}=\dfrac{3^5}{0.3}=810\)
c: \(=\dfrac{2^{12}\cdot3^6+2^3\cdot3^3\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\dfrac{2^{12}\cdot3^6+2^6\cdot3^4\cdot5}{2^{11}\cdot3^{11}\cdot5}\)
\(=\dfrac{2^6\cdot3^4\left(2^6\cdot3^2+5\right)}{2^{11}\cdot3^{11}\cdot5}=\dfrac{1}{2^5}\cdot\dfrac{1}{3^7}\cdot\dfrac{581}{5}=\dfrac{581}{2^5\cdot3^7\cdot5}\)
tìm chữ số 0 tận cùng 8.8^2.8^3. ... .8^20.5^1.5^2. ... .5^100 ?
\(\dfrac{8^5\cdot\left(-5\right)^8+\left(-2\right)^5\cdot10^9}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{2^{15}\cdot5^8-2^5\cdot10^9}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^{10}\cdot5^{18}-10^9\right)\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^2\cdot10^8-10^9\right)\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^2-10\right)\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(4-10\right)\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-6\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot2\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot2^6\cdot10^8}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot64\cdot10^8}{2^{16}\cdot5^7+20^8}\)
\(\dfrac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}=\dfrac{\left(2^3\right)^5.5^8+\left(-2\right).2^4.2^9.5^9}{2^{16}.5^7+\left(2^2\right)^8.5^8}\) \(=-\dfrac{2^{15}.5^8+2^{14}.5^9}{2^{16}.5^7+2^{16}.5^8}=-\dfrac{2^{14}.5^8.\left(2+5\right)}{2^{16}.5^7.\left(1+5\right)}=-\dfrac{5.7}{4.6}=-\dfrac{35}{24}\)
(530 + 520) : ( 520 + 510) = 520.(510+1):510.(510+1)
=520:510=510
\(\frac{20^5.5^{10}}{100^5}=\frac{4^5.5^5.25^5}{100^5}=\frac{100^5.5^5}{100^5}=5^5\)