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( 2003 x 58 + 52 x 2003 - 10 x 2003 ) + ( 670 - 355 ) x 100
= 200300 + 315 x100
= 200300 + 31500
= 231800
\(=2003\times\left(58+52-10\right)+335\times100\)
\(=100\times\left(2003+335\right)=233800\)
(2003 x 58 + 52 x 2003 - 10 x 2003) + (670-335) x 100
= 2003 x ( 58 + 52 - 10 ) + 335 x 100
= 2003 x 100 + 335 x 100
= ( 2003 + 335 ) x 100
= 2338 x 100
233 800
\(100-7\cdot\left(x-5\right)=58\)
\(7\cdot\left(x-5\right)=100-58\)
\(7\cdot\left(x-5\right)=42\)
\(x-5=\frac{42}{7}=6\)
\(\Rightarrow x=6+5\)
\(\Rightarrow x=11\)
\(\frac{2004\times13+1990+2002\times2003}{2003+2003\times501+506\times2003}=\frac{2004\times13+1990+2002}{\left(2003+1\right)\times501+506}=\frac{2004\times4205}{2004\times1007}=\frac{4205}{1007}\)
Rút gọn ta có:
\(=\frac{2003}{2004}x\frac{2003}{2005}x\frac{2004}{2005}\)
\(=\frac{2003x2003x2004}{2004x2005x2005}\)
Giản bước ta được: \(\frac{2003x2003}{2005x2005}\)
Ta có : \(\frac{2003}{2004}\)x\(\frac{200320032003}{200520052005}\)x\(\frac{20042004}{20052005}\)
= \(\frac{2003}{2004}\)x\(\frac{2003x100010001}{2005x100010001}\)x\(\frac{2004x10001}{2005x10001}\)
= \(\frac{2003x2003x2004}{2004x2005x2005}\)
= \(\frac{2003x2003}{2005x2005}\)
Bạn rút gọn hộ mik nhaa !!!
\(\frac{\left(2002+1\right)\times1986+2002\times17+2020}{2003\times\left(2003+1\right)-2003\times2003}\times X=4008\)
\(\frac{2002\times1986+2002\times17+1986+2020}{2003}\times X=4008\)
\(\frac{2002\times\left(1986+17\right)+4006}{2003}\times X=4008\)
\(\frac{2002\times2003+4006}{2003}\times X=4008\)
\(\left(2002+2\right)\times X=4008\)
\(2004\times X=4008\)
\(X=2\)
Vậy X = 2.
a =2004.10+1992+2002+2004
= 2004(10+1)+3994
= 2004.11+3994=26038
b =2003(1+493+1520)=2003.2024=4054072
( 2003 x 58 + 52 x 2003 - 10 x 2003 ) + ( 670 - 335 ) x 100
= 2003 x ( 58 + 52 -10 ) + 315 x 100
= 2003 x 100 + 315 x 100
= 200300 + 31500
= 231800
( 2003 x 58 + 52 x 2003 - 10 x 2003 ) + ( 670 - 355 ) x 100
= 200300 + 315 x100
= 200300 + 31500
= 231800