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a)\(x+12=-23+5\)
\(< =>x+12+23-5=0\)
\(< =>x+30=0\)
\(< =>x=-30\)
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Câu 1:
(57 + 59).(68 + 610).(24 - 42) = (57 + 59).(68 + 610).(24 - 24) = (57 + 59).(68 + 610).0 = 0
Câu 2:
(73 + 75).(54 + 56).(33.3 - 92) = (73 + 75).(54 + 56).(34 - 34) = (73 + 75).(54 + 56).0 = 0
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a/ => (x2 - 5)(x + 5)(x - 5) = 0
=> x2 - 5 = 0 => x2 = 5 => x = \(+-\sqrt{5}\) (loại)
hoặc x + 5 = 0 => x = -5
hoặc x - 5 = 0 => x = 5
Vậy x = 5 ; x = -5
b/ => x + 5 = 0 => x = -5
hoặc 9 + x2 = 0 => x2 = -9 (vô nghiệm)
Vậy x = -5
c/ => x + 3 = 0 => x = -3
hoặc x2 + 1 = 0 => x2 = -1 (vô nghiệm)
Vậy x = -3
d/ => (x + 5)(x + 2)(x - 2) = 0
=> x + 5 = 0 => x = -5
hoặc x + 2 = 0 => x = -2
hoặc x - 2 = 0 => x = 2
Vậy x = -5 ; x = -2; x = 2
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a) -2 /3 x + 1/5 = 3/10
-2/3x =1/10
x = -3/20
vậy x = -3/20
b) 25/9 - 12/13x = 7/
12/13x = 2
x = 13/6
c) (x) - 3/4 =5/3
(x) = 29/12
x = 29/12 ; -29/-12
d) x = 11/2
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a, \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.9^2.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{5.2.2^{29}.3^{18}-2^{29}.3^2.3^{18}}{5.2^{28}.3.3^{18}-7.2.2^{28}.3^{18}}=\frac{\left(5.2-3^2\right).2^{29}.3^{18}}{\left(5.3-7.2\right).2^{28}.3^{18}}=2\)
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bài 1
a) \(8^7\times2^3-8^8=8^8-8^8=0\)
b) \(27-3^3=3^3-3^3=0\)
\(2^3\times4\div2^4=2^5\div2^4=2\)
Bài 2:
a) \(x-2^3=0\Rightarrow x=2^3\)
\(2^3-x=1\Rightarrow x=8-1\Rightarrow x=7\)
\(8-2^x=0\Rightarrow2^x=8\Rightarrow2^x=2^3\Rightarrow x=3\)
\(x^n=0\Rightarrow x=0\) với mọi \(n\in N\)
b) \(3^x=27\Rightarrow3^x=3^3\Rightarrow x=3\)
\(2^x\div2^5=1\Rightarrow2^x\div2^5=2^0\Rightarrow2^x=2^5\Rightarrow x=5\)
\(3^{2x}=0\Rightarrow3^{2x}=3^0\Rightarrow2x=0\Rightarrow x=0\)
20 x 29 : 8
= 1 x 512 : 8
= 512 : 8
= 64
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