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minh moi bn vao link nay dang ky roi tra loi minigame nha : https://alfazi.edu.vn/question/5b7768199c9d707fe5722878

Bài 1: Tính hợp lí
a) ( -2 ) + 7 + ( -12 ) + 17+ ....+ ( -52 ) + 57
= 5 + 5 + .... + 5 ( có 6 số 5 )
= 5 . 6
= 30
b) ( -30 ) + ( -29 ) + ... + 48 + 49 + 50
= [ ( - 30 ) + 30 ] + [ ( - 29 ) + 29 ] + .... + [ ( - 1 ) + 1 ] + 0 + 31 + 32 + 33 + .... + 49 + 50
= 0 + 0 + .... + 0 + 0 + 31 + 32 + 33 + .... + 49 + 50
= 0 + 31 + 32 + 33 + .... + 49 + 50
= (31 + 49 ) + (32 + 48 ) + .... + ( 43 + 37 ) + ( 44 + 36 ) + ( 40 + 50 )
= 80 + 80 + .... + 80 + 80 + 90 ( 9 số 80 )
= 80 . 9 + 90
= 720 + 90
= 810

a) \(\frac{22}{7}:\left(11-x\right)+\frac{2}{3}=\frac{7}{5}\)
\(\frac{22}{7}:\left(11-x\right)=\frac{7}{5}-\frac{2}{3}\)
\(\frac{22}{7}:\left(11-x\right)=\frac{11}{15}\)
\(11-x=\frac{22}{7}:\frac{11}{15}\)
\(11-x=\frac{30}{7}\)
\(x=11-\frac{30}{7}\)
\(x=\frac{47}{7}\)
b) \(22.\left(x+1\right)-12,5=53,5\)
\(22.\left(x+1\right)=53,5+12,5\)
\(22.\left(x+1\right)=66\)
\(x+1=66:22\)
\(x+1=3\)
\(x=3-1\)
\(x=2\)
c) \(\left(x-\frac{1}{2}\right).\frac{5}{2}+\frac{1}{2}=\frac{7}{4}\)
\(\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{7}{4}-\frac{1}{2}\)
\(\left(x-\frac{1}{2}\right).\frac{5}{2}=\frac{5}{4}\)
\(x-\frac{1}{2}=\frac{5}{4}:\frac{5}{2}\)
\(x-\frac{1}{2}=\frac{1}{2}\)
\(x=\frac{1}{2}+\frac{1}{2}\)
\(x=1\)
a)22/7:(11-x)=7/5-2/3
22/7:(11-x)=11/15
11-x=22/7:11/15
11-x=30/7
x=11-30/7
x=47/7
vậy x=47/7
b)22.(x+1)=53,5+12,5
22.(x+1)=66
x+1=66:2
x+1=3
x=3-1
x=2
vậy x=2
c)(x-1/2).5/2=7/4-1/2
(x-1/2).5/2=5/4
x-1/2=5/4:5/2
x-1/2=1/2
x=1/2+1/2
x=1
vậy x=1
bạn hãy tích đúng cho mình nhé

34 x 52 - 34 + 34 x 49
= 34 x 52 - 34 x 1+ 34 x 49
= 34 x ( 52 - 1 + 49 )
= 34 x 100
= 3400

\(7^{2x-3}=7^2\cdot5+7^2\cdot2\)
\(7^{2x-3}=7^2\left(5+2\right)\)
\(7^{2x-3}=7^2\cdot7\)
\(7^{2x-3}=7^3\)
\(2x-3=3\)
\(2x=6\)
\(x=3\)
\(7^{2x-3}-2.49=49.5\)
\(7^{2x-3}-2.49=245\)
\(7^{2x-3}-2=245:49\)
\(7^{2x-3}-2=5\)
\(7^{2x-3}=5+2\)
\(7^{2x-3}=7\)
2x-3=1
2x=1+3
2x=4
x=4:2
x=2
vậy x=2

bài làm
2 - ( | x | + 7 ) = -52
<=> | x | + 7 = 2 + 52
<=> | x | + 7 = 54
<=> | x | = 54 - 7 = 47
<=> x = 47 hoặc x = -47.
Vậy....
2-(|x|+7)=-52
|x|+7=2+52
|x|+7=54
|x|=54-7
|x|=47
\(\orbr{\begin{cases}x=47\\x=-47\end{cases}}\)
Vậy x=47;x=-47