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a) Ta có:
1; 4; 7;...; 100 có (100 - 1) : 3 + 1 = 34 (số)
1 + 4 + 7+ ... + 100 = (100 + 1) × 34 : 2
= 101 × 17
(1 + 4 + 7 + ... + 100) : a = 17
101 × 17 : a = 17
a = 101 × 17 : 17
a = 100
b) (X - 1/2) × 5/3 = 7/4 - 1/2
(X - 1/2) × 5/3 = 5/4
X - 1/2 = 5/4 : 5/3
X - 1/2 = 3/4
X = 3/4 + 1/2
X = 5/4
a) (1 + 4 + 7 +...+ 100) : a = 17
1717 : a = 17
a = 101
b) \(\left(x-\dfrac{1}{2}\right)\times\dfrac{5}{3}=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\left(x-\dfrac{1}{2}\right)\times\dfrac{5}{3}=\dfrac{10}{8}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{10}{8}\div\dfrac{5}{3}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{10}{8}\times\dfrac{3}{5}\)
\(\left(x-\dfrac{1}{2}\right)=\dfrac{3}{4}\)
\(x-\dfrac{1}{2}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}+\dfrac{1}{2}\)
\(x=\dfrac{5}{4}\)
a) \(=\frac{1}{6}x\frac{5}{2}+\frac{3}{7}\)
\(=\frac{5}{12}+\frac{3}{7}\)
\(=\frac{71}{84}\)
b) \(=\frac{8}{5}-\frac{1}{2}x\frac{1}{3}\)
\(=\frac{8}{5}-\frac{1}{6}\)
\(=\frac{43}{30}\)
a, \(\frac{1}{6}:\frac{2}{5}+\frac{3}{7}\)
\(=\frac{1}{6}\cdot\frac{5}{2}+\frac{3}{7}\)
\(=\frac{5}{12}+\frac{3}{7}\)
\(=\frac{71}{84}\)
b, \(\frac{8}{5}-\frac{1}{2}\cdot\frac{1}{3}\)
\(=\frac{8}{5}-\frac{1}{6}\)
\(=\frac{43}{30}\)
\(\dfrac{3}{8}+\left(a-\dfrac{5}{24}\right):\dfrac{1}{24}=1\\ \Rightarrow\left(a-\dfrac{5}{24}\right):\dfrac{1}{24}=1-\dfrac{3}{8}\\ \Rightarrow\left(a-\dfrac{5}{24}\right):\dfrac{1}{24}=\dfrac{8}{8}-\dfrac{3}{8}\\ \Rightarrow\left(a-\dfrac{5}{24}\right):\dfrac{1}{24}=\dfrac{5}{8}\\ \Rightarrow a-\dfrac{5}{24}=\dfrac{5}{8}\times\dfrac{1}{24}\\ \Rightarrow a-\dfrac{5}{24}=\dfrac{5}{192}\\ \Rightarrow a=\dfrac{5}{192}+\dfrac{5}{24}\\ \Rightarrow a=\dfrac{15}{64}\)
Lần sau em đăng đúng môn học nha