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`3^{x} + 4^{2} = 19^{6} : 19^{3} . 19^{2} - 3 . 1^{2015}`
`<=>3^{x} + 4^{2} = 19^{6} : 19^{5} - 3 . 1`
`<=>3^{x} + 16 = 19 - 3`
`<=>3^{x} + 16 = 16`
`<=>3^{x} = 16 - 16`
`<=>3^{x} = 0`
`=>x \in \emptyset`
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bài 1 tính giá trị biểu thức
( - 25 ) nhân ( -3 ) nhân x với x = 4
\(\left(-25\right).\left(-3\right).4\)
\(=\left(-25\right).4.\left(-3\right)\)
\(=-100.\left(-3\right)=300\)
( -1 ) nhân ( -4 ) nhân 5 nhân 8 nhân y với y =25
\(\left(-1\right).\left(-4\right).5.8.25\)
\(=4.5.8.25=4.25.5.8\)
\(=100.40=40000\)
( 2ab mũ 2 ) : c với a =4 ; b= -6 ; c =12
\(\left(2.4.\left(-6\right)\right)^2:12\)
\(=\left(-48\right)^2:12\)
\(=2304:12=192\)
[ ( -25 ) nhân ( - 27 ) nhân ( -x ) ] : y với x = 4 ; y = -9
\(\left[\left(-25\right).\left(-27\right).\left(-4\right)\right]:-9\)
\(=-2700:\left(-9\right)\)
\(=300\)
(a mũ 2 _ b mũ 2) : ( a + b ) nhân ( a _ b ) với a + 5 , b = -3
\(\left(5^2-\left(-3\right)^2\right):\left(5-3\right).\left(5+3\right)\)
\(=16:2.8\)
\(=8.8=64\)
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\(23\left(x-1\right)+19=65\)
\(23\left(x-1\right)=65-19\)
\(23\left(x-1\right)=46\)
\(x-1=46:23\)
\(x-1=2\)
\(x=2+1\)
\(x=3\)
\(5x+3x=88\)
\(x\left(5+3\right)=88\)
\(x.8=88\)
\(x=88:8\)
\(x=11\)
\(x^3=64\)
\(x^3=4^3\)
\(\Rightarrow x=4\)
\(\left(5x-4\right):7-2=6\)
\(\left(5x-4\right):7=6+2\)
\(\left(5x-4\right):7=8\)
\(5x-4=8.7\)
\(5x-4=56\)
\(5x=56+4\)
\(5x=60\)
\(x=60:5\)
\(x=12\)
\(x^{50}=x\)
\(\Rightarrow x=1\)
\(4.2^x-3=125\)
\(4.2^x=125+3\)
\(4.2^x=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
k mk nha
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\(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x.\left(x+1\right)}=\frac{4}{15}\)( đã sửa đề từ x+(x+1) thành x.(x+1) )
\(\Rightarrow\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{4}{15}\)( Áp dụng \(\frac{1}{a.\left(a+1\right)}=\frac{1}{a}-\frac{1}{a+1}\))
\(\Rightarrow\frac{1}{3}-\frac{1}{x+1}=\frac{4}{15}\)
\(\Rightarrow\frac{x+1-3}{3.\left(x+1\right)}=\frac{4}{15}\)
\(\Rightarrow\frac{x-2}{3x+3}=\frac{4}{15}\)
\(\Rightarrow4.\left(3x+3\right)=15.\left(x-2\right)\)
\(\Rightarrow12x+12=15x-30\)
\(\Rightarrow12x=15x-30-12\)
\(\Rightarrow12x-15x=-30-12\)
\(\Rightarrow-3x=-42\)
\(\Rightarrow x=14\)
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4x - 15 = - 75 - x
=> 4x + x = - 75 + 15
=> 5x = - 50
=> x = -10
Vậy x = -10
2x . ( x - 3 ) = 0
\(\Rightarrow\orbr{\begin{cases}2x=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy \(x\in\left\{0;3\right\}\)
Học tốt
K cần tk
4.x-15=-75-x <=> 5.x=-60 <=> x=-12
2.x.(x-3)=0 <=> x=0 hoặc x-3=0
<=>x=0 hoặc x=3
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bài 1) thực hiện phép tính
a) \(4^5-81:3^2=1024-9=1015\)
b) \(3^2.22-3^2.12=3^2.2\left(11-6\right)=18.5=90\)
c) \(2^3.15-\left[115-\left(12-5\right)\right]=120-\left(115-12+5\right)=120-115+12-5=12\)
d) \(3.3^2-19^{21}:19^{20}+2010^0=27-19+1=9\)
e)\(7^{25}:\left(7^{21}.46+7^{21}.3\right)=7^{25}:\left(7^{21}.49\right)=\frac{7^{21}.7^4}{7^{21}.49}=\frac{2401}{49}=49\)
bài 2)Tim x
a) 716 - (x - 143) = 695
<=> x - 143 = 716 - 695
<=> x - 143 = 21
<=> x = 21 + 143
<=> x = 164
vậy x = 164
\(2.\left(x-3\right).\left(4-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=0\\4-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\2x=4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=2\end{cases}}\)
Vậy \(x\in\left\{2;3\right\}\)
\(2.\left(x-3\right).\left(4-2x\right)=0\)
\(\left(2x-6\right).\left(4-2x\right)=0\)
\(\Rightarrow\hept{\begin{cases}2x-6=0\\4-2x=0\end{cases}\Rightarrow\hept{\begin{cases}x=3\\x=2\end{cases}}}\)