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b) \(\frac{3}{x-5}=\frac{-4}{x+2}\)
=> 3.(x + 2) = (x - 5). (-4)
= 3x + 6 = -4x + 20
= 3x - 4x = 26
=> -x = 26
=> x = -26
c) \(\frac{x}{-2}=\frac{-8}{x}\)
=> x.x = -2 . (-8)
=> x2 = 16
=> x = 4
t i c k nha!!! 645646677778879078452352543546456457567564546567
a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\)
b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\)
đúng hết đấy nhé mình tính kĩ lắm ko sai đâu
chúc may mắn
a)\(\left(\frac{3}{29}-\frac{1}{5}\right)\cdot\frac{29}{3}\)
\(=\left(\frac{3}{29}\cdot\frac{29}{3}\right)-\left(\frac{1}{5}\cdot\frac{29}{3}\right)\)
\(=1-\frac{29}{15}\)
\(=\frac{-14}{15}\)
b)\(\frac{16}{15}\cdot\frac{-5}{14}\cdot\frac{54}{24}\cdot\frac{56}{21}\)
=\(=\frac{16\cdot\left(-5\right)\cdot54\cdot56}{15\cdot14\cdot24\cdot21}\)
\(=\frac{2^4\cdot\left(-5\right)\cdot2\cdot3^3\cdot2^3\cdot7}{3\cdot5\cdot7\cdot2\cdot2^3\cdot3\cdot7}\)
\(=2^4\)
c)\(\frac{37}{7}\cdot\frac{8}{11}+\frac{37}{7}\cdot\frac{5}{11}-\frac{37}{7}\cdot\frac{2}{11}\)
\(=\frac{37}{7}\cdot\left(\frac{8}{11}+\frac{5}{11}-\frac{2}{11}\right)\)
\(=\frac{37}{7}\cdot1\)
\(=\frac{37}{7}\)
Đúng nhớ k nhen!
\(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3\times21}{7}=9\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Leftrightarrow3.\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow3x+4x=20-6\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
3/2-(43/8+X-75/24):50/3=1/2
3/2-(43/8+X-75/24)=25/3
43/8+X-75/24=-41/6
43/8+X=(-41/6)+75/24
43/8+X=(-85/24)
X=85/24-43/8
X=-109/12
Vậy X=-109/12
\(\frac{3}{2}-\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}\)\(=\frac{1}{2}\)
\(\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}=\frac{3}{2}-\frac{1}{2}\)
\(\left(5\frac{3}{8}+x-\frac{75}{24}\right):16\frac{2}{3}=1\)
\(5\frac{3}{8}+x-\frac{75}{24}\)\(=1.16\frac{2}{3}\)
\(5\frac{3}{8}+x-\frac{75}{24}=\frac{50}{3}\)
\(5\frac{3}{8}+x=\frac{50}{3}+\frac{75}{24}\)
\(5\frac{3}{8}+x=\frac{475}{24}\)
\(x=\frac{475}{24}-5\frac{3}{8}\)
\(x=\frac{173}{12}\)
\(1-\left(5\frac{3}{8}+x+7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x+\frac{173}{24}\right):\frac{50}{3}=0\)
\(\left(\frac{151}{12}+x\right):\frac{50}{3}=1\)
\(\frac{151}{12}+x=\frac{50}{3}\)
\(x=\frac{50}{3}-\frac{151}{12}\).
\(x=\frac{49}{12}\)
\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)\(\Rightarrow2-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\Rightarrow\frac{43}{8}+x-\frac{173}{24}=2\times\frac{50}{3}\)
\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{100}{3}\Rightarrow x=\frac{100}{3}+\frac{173}{24}-\frac{43}{8}\Rightarrow x=\frac{211}{6}=35\frac{1}{6}\)