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\(a.\frac{1}{5}+\frac{7}{3}+6+5\)
\(=\frac{30}{150}+\frac{350}{150}+\frac{25}{150}+\frac{30}{150}\)
\(=\frac{30+350+25+30}{150}\)
\(=\frac{435}{150}\)
\(b.\frac{9}{10}+\frac{7}{2}+\frac{1}{5}\)
\(=\frac{9}{10}+\frac{35}{10}+\frac{2}{10}\)
\(=\frac{9+35+2}{10}\)
\(=\frac{46}{10}\)
\(c.\frac{9}{2}-\frac{1}{5}\)
\(=\frac{45}{10}-\frac{2}{10}\)
\(=\frac{45-2}{10}\)
\(=\frac{43}{10}\)
\(d.\frac{7}{3}-\frac{5}{21}\)
\(=\frac{49}{21}-\frac{5}{21}\)
\(=\frac{49-5}{21}\)
\(=\frac{44}{21}\)
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Trình bày hết ra thì dài lắm. Mình nói cái chính rồi bạn làm nốt.
Cách 1 ở tất cả các câu: Tính bình thường như đề cho
a) Cách 2: \(\frac{5}{7}\times\frac{3}{4}+\frac{5}{7}\times\frac{1}{2}\)
b) Cách 2: \(\frac{13}{21}\times\left(\frac{5}{7}+\frac{2}{7}\right)\)
c) Cách 2: \(\frac{2}{5}\times\frac{1}{2}+\frac{2}{5}\times\frac{1}{3}\)
d) Cách 2: \(\frac{17}{21}\times\left(5+\frac{2}{5}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
[6: 3/5 - 7/6 x 6/7] : [ 21/5 x 10/11 + 57/11]
= 9 : 9
= 1
\(\left(6:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}\right):\left(\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}\right)\)
\(=\left(10-1\right):\left(\frac{42}{11}+\frac{57}{11}\right)\)
\(=9:9\)
\(=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{7}+\frac{5}{7}=\frac{7}{7}=1\)
\(\frac{8}{15}+\frac{6}{15}=\frac{14}{15}\)
\(\frac{2}{3}+\frac{3}{9}+\frac{4}{9}=\frac{6}{9}+\frac{3}{9}+\frac{4}{9}=\frac{9}{9}+\frac{4}{9}=\frac{13}{9}\)
\(2-\dfrac{5}{7}+\dfrac{9}{21}\)
\(=2-\dfrac{5}{7}+\dfrac{3}{7}\)
\(=\dfrac{14}{7}-\dfrac{5}{7}+\dfrac{3}{7}\)
\(=\dfrac{12}{7}\)
\(2-\dfrac{5}{7}+\dfrac{9}{21}=\dfrac{42}{21}-\dfrac{15}{21}+\dfrac{9}{21}=\dfrac{12}{7}\)