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a)(x-2)5=243
\(\Leftrightarrow\left(x-2\right)^5=3^5\)
\(\Rightarrow x^5=3^5+2^5=5^5\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 32 < 2n > 128
<=> 25 < 2n > 27
<=> n = 8 ; 9 ; 10...
b) 2 . 16 < 2n > 4
<=> 21 . 24 < 2n > 4
<=> 25 < 2n > 4
<=> n = 5 ; 6 ; 7 ;...
c) ( 22 : 4 ) . 2n = 4
<=> 1 . 2n = 4
<=> 2n = 4
<=> 2n = 22
<=> n = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5^x.5=625\)
\(\Rightarrow5^x=125=5^3\)
\(\Rightarrow x=3\)
b) \(3^x=9.27\)
\(\Rightarrow3^x=3^2.3^3=3^5\)
\(\Rightarrow x=5\)
c) \(\left(x-6\right)^2=9\) .
\(\Rightarrow\orbr{\begin{cases}x-6=-3\\x-6=3\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=9\end{cases}}\)
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3x - 23 = 32 + 114
=> 3x - 8 = 9 + 1
=> 3x - 8 = 10
=> 3x = 18
=> x = 6
vậy_
1)\(3x-2^3=3^2+1^{14}=9+1=10\)\(10\)
\(\Rightarrow3x-8=10\Rightarrow3x=10+8=18\)
\(\Rightarrow x=18:3=6\)
2)\(2^5x-3^3x=121-\frac{15}{15}\)
\(\Rightarrow x.\left(2^5-3^3\right)=121-1\)
\(\Rightarrow x.5=120\Rightarrow x=120:5=24\)
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\(\left(x-6\right)^2=9=3^2=\left(-3\right)^2=>\orbr{\begin{cases}x-6=3\\x-6=-3\end{cases}}=>\orbr{\begin{cases}x=9\\x=3\end{cases}}\)
\(5^{x+1}=125=5^3=>x+1=3=>x=2\)
\(5^{2x-3}-2.5^2=3.5^2=>5^{2x-3}=3.5^2+2.5^2=\left(3+2\right).5^2=5.5^2=125=5^3\)
\(=>2x-3=3=>2x=6=>x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/9.27n = 3n
=> 27n : 3n = : 1/9
=> 9n = 9 = 91
=> n = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
theo mình nghĩ là
x=1
đúng tk nhé
sai sửa
làm kiểu gì bn