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lộn
\(\left|\left(-3\right)^2-\left(-2\right)^3\right|:\left|4-\left(-2\right)^2+30^0\right|\)
\(=\left|9-\left(-8\right)\right|:\left|4-4+1\right|\)
\(=\left|9+8\right|:\left|1\right|\)
\(=\left|17\right|:1\)
\(=17:1\)
\(=17\)
\(\left[\left(-3\right)^2-\left(-2\right)^3\right]:\left[4-\left(-2\right)^2+30^0\right]\)
\(=\left[9-\left(-8\right)\right]:\left(4-4+1\right)\)
\(=\left(9+8\right):1\)
\(=17:1\)
\(=17\)
A =118.75
B=125 -5 .(3.X -1) =25
5.(3.X-1) =100
3.X-1=20
3X =21
X=7
[130 - 3.(5.24 - 52.2) : 23]
= [ 130 - 3.30:23]
= 130 - 11,25
= 118,75
b) 125 -5.(3x-1) = 55:53
125 -5.(3x-1) = 25
5.(3x-1) = 100
3x-1 = 20
3x = 21
x = 7
c) 4x-1 + 40 = 65
4x:4 + 1 = 65
4x:4 = 64
4x = 256 = 44
=> x = 4
Gọi tổng là S, Ta có
S=1+2+2^2+2^3+...+2^2016+2^2017
2S=2+2^2+2^3+2^4+...+2^2017+2^2018
2S-S=2+2^2+2^3+2^4+...+2^2017+2^2018-(1+2+2^2+2^3+...+2^2016+2^2017)
S=2+2^2+2^3+2^4+...+2^2017+2^2018-1-2-2^2-2^3-...-2^2016-2^2017
=2^2018-1
Vậy S=2^2018-1
Nhớ tíck cho mình nha :)
Gọi là A nhé
=>2A=2+2^2+2^3+...+2^2018
=>2A-A=(2+2^2+2^3+...+2^2018)-(1+2+...+2^2017)
=>A=2^2018-1
k nhé
a, \(-17.53-21.\left(-17\right)-17.17^0\)
\(=\)\(-17.\left(53-21\right)-17.1\)
\(=\) \(-17.32-17\)
\(=\)\(-544-17\)
\(=-561\)
b, \(\left|-2^2.2^3-3^5\right|+3^5+2009^0-\left(-1\right)^{101}\)
\(=\left|-4.8-243\right|+243+1+1^{101}\)
\(=\left|-32-243\right|+243+1+1\)
\(=\left|-275\right|+243+1+1\)
\(=275+243+1+1\)
\(=518+1+1\)
\(=519+1\)
\(=520\)
:)
a) (52020 - 52019) : 52018
= 52019(5-1) : 52018
= 5.(5-1)
= 5.4
= 20
(2.x-15)5=(2.x-15)3
=>(2.x-15)5-(2.x-15)3=0
=>(2.x-15)3.[(2.x-15)2-1]=0
=>(2.x-15)3=0=>2.x-15=0=>2.x=15=>x=15/2
hoặc (2.x-15)2-1=0=>(2.x-15)2=1=>2.x-15=-1,1=>2.x=14,16=>x=7,8
Vậy x=7,15/2,8
2x.3x+5=4.9
=>(2.3)x+5=36
=>6x=36-5
=>6x=31
=>Vô lí
\(\left[17^2-\left(3-5\right)^2\right].\left[2^3-\left|-1-2\right|^2\right]\)
\(=\left[289-\left(-2\right)^2\right].\left[2^3-\left|-3\right|^2\right]\)
\(=\left(289-4\right).\left(8-3^2\right)\)
\(=285.\left(8-9\right)\)
\(=285.\left(-1\right)\)
\(=-285\)
(289 - 4) .[8+(-1)]^2
= 285. 49
=13965