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(35*x+3)*19=165-13
(35*x+3)*19=152
35*x+3=152/19
35*x+3=8
35*x=8-3
35*x=5
x=35/5
x=7
165 - (35 : x + 3). 19 = 13
(35 : x + 3). 19 =165-13
(35 : x + 3). 19 =152
35:x+3= 152:19
35:x+3=8
35: x= 8-3
35:x= 5
x= 35:5
x= 7
Vậy..
\(165-\left(35:x+3\right).19=13\)
\(\Rightarrow\left(35:x+3\right).19=165-13\)
\(\Rightarrow\left(35:x+3\right).19=152\)
\(\Rightarrow\left(35:x+3\right)=152:19\)
\(\Rightarrow\left(35:x+3\right)=8\)
\(\Rightarrow35:x=8-3\)
\(\Rightarrow35:x=5\)
\(\Rightarrow x=35:5\)
\(\Rightarrow x=7\)
Vậy x = 7
Đáp án là A
Ta có: 165 - (35:x + 3).19 = 13
⇔ (35:x + 3).19 = 165 - 13
⇔ (35:x + 3).19 = 152
⇔ (35:x + 3) = 152:19 = 8
⇔ 35:x = 5
⇔ x = 7
a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)
\(\Leftrightarrow\left(x:3+17\right):10+48=50\)
\(\Leftrightarrow\left(x:3+17\right):10=2\)
\(\Leftrightarrow x:3+17=20\)
\(\Leftrightarrow x:3=3\)
hay x=9
b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Leftrightarrow119-\left(x-6\right)=102\)
\(\Leftrightarrow x-6=17\)
hay x=23
c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)
\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)
\(\Leftrightarrow\left(35:x+3\right)=8\)
\(\Leftrightarrow35:x=5\)
hay x=7
4. ( x - 250 ) : 6 = 64 - 12
( x- 250 ) : 6 = 52
x - 250 = 312
x = 562
5. 10x = 1030
=> x = 103
6. 30x = 120
x = 4
7. \(x=2023\)
\(8.165-\left(35:x+3\right).19=13\)
\(\left(35:x+3\right).19=152\)
\(35:x+3=8\)
\(35:x=5\)
\(x=7\)
4) \(\left(x-250\right)\div6=4^3-2^2\times3\)
\(\left(x-250\right)\div6=64-4\times3\)
\(\left(x-250\right)\div6=64-12=52\)
\(x-250=52\times6=312\)
\(x=312+250\)
\(x=562\)
5) \(2x+3x+5x=1030\)
\(x\left(2+3+5\right)=1030\)
\(10x=1030\)
\(x=1030\div10\)
\(x=103\)
6) \(15x-35x+50x=120\)
\(x\left(15-35+50\right)=120\)
\(30x=120\)
\(x=120\div30\)
\(x=4\)
7) \(\dfrac{1}{2}x+\dfrac{1}{6}x+\dfrac{1}{3}x=2023\)
\(x\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)=2023\)
\(x\times1=2023\)
\(x=2023\)
8) \(165-\left(35\div x+3\right)\times19=13\)
\(\left(35\div x+3\right)\times19=165-13\)
\(\left(35\div x+3\right)\times19=152\)
\(35\div x+3=152\div19=8\)
\(35\div x=8-3=5\)
\(x=35\div5\)
\(x=7\)
165 - (35 : x + 3).9 = 13
⇒ (35 : x + 3).9 = 165 - 13
⇒ (35 : x + 3).9 = 152
⇒ 35 : x + 3 = 152/9
⇒ 35 : x = 152/9 - 3
⇒ 35 : x = 125/9
⇒ x = 35 : 125/9
⇒ x = 35 . 9/125
⇒ x = 63/25
Ok