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a. \(\frac{-3}{7}+\frac{15}{26}-\frac{2}{13}+\frac{3}{7}\)
\(=\left(\frac{-3}{7}+\frac{3}{7}\right)+\frac{15}{26}-\frac{2}{13}\)
\(=\frac{15}{26}-\frac{2}{13}\)
\(=\frac{15}{26}-\frac{4}{26}=\frac{11}{26}\)
b. \(\frac{3}{7}-\frac{5}{3}\div\frac{1}{9}-\frac{3}{7}\)
\(=\frac{3}{7}-\frac{5}{3}\times\frac{9}{1}-\frac{3}{7}\)
\(=\frac{3}{7}-15-\frac{3}{7}\)
\(=-15\)
\(-\frac{3}{7}+\frac{15}{26}-\frac{2}{13}+\frac{3}{7}=\frac{15}{26}-\frac{2}{13}=\frac{11}{26}\)
\(\frac{2.3}{7}-\frac{5}{3}:\frac{1}{9}-\frac{3}{7}=\frac{6}{7}-15-\frac{3}{7}=\frac{3}{7}-15=-\frac{102}{7}\)

b) 1-3+5-7+9-11+......+2005-2007
=(1-3)+(5-7)+(9-11)+.....+(2005-2007)
=(-2)+(-2)+(-2)+......+(-2)
=(-2).1004
=(-2008)
c) 1+2+3-4-5-6+7+8+9-10-11-12+...+97+98+99-100-101-102
=(1+2+3-4-5-6)+(7+8+9-10-11-12)+.....+(97+98+99-100-101-102)
=(-9)+(-9)+....+(-9)
=(-9).17
=(-153)
Xin lỗi nha 2 dòng cuối mk làm sai
b)1-3+5-7+9-11+......+2005-2007
=(1-3)+(5-7)+(9-11)+....+(2005-2007)
=(-2)+(-2)+(-2)+....+(-2)
=(-2).502
=(-1004)

`@` `\text {Ans}`
`\downarrow`
`2+(x+3)=7`
`\Rightarrow x+3=7-2`
`\Rightarrow x+3=5`
`\Rightarrow x=5-3`
`\Rightarrow x=2`
`5+(3+x)=10`
`\Rightarrow 3+x=10-5`
`\Rightarrow 3+x=5`
`\Rightarrow x=5-3`
`\Rightarrow x=2`
`(4+x)+1=7`
`\Rightarrow 4+x=7-1`
`\Rightarrow 4+x=6`
`\Rightarrow x=6-4`
`\Rightarrow x=2`
`(x+5)+3=9`
`\Rightarrow x+5=9-3`
`\Rightarrow x+5=6`
`\Rightarrow x=6-5`
`\Rightarrow x=1`
`(x-1)-4=7`
`\Rightarrow x-1=7+4`
`\Rightarrow x-1=11`
`\Rightarrow x=11+1`
`\Rightarrow x=12`
`4-(6-x)=1`
`\Rightarrow 6-x=4-1`
`\Rightarrow 6-x=3`
`\Rightarrow x=6-3`
`\Rightarrow x=3`
\(2+\left(x+3\right)=7\)
\(\Rightarrow2+x+3=7\)
\(\Rightarrow x+5=7\)
\(\Rightarrow x=2\)
\(5+\left(3+x\right)=10\)
\(\Rightarrow5+3+x=10\)
\(\Rightarrow x+8=10\)
\(\Rightarrow x=2\)
\(\left(4+x\right)+1=7\)
\(\Rightarrow4+x+1=7\)
\(\Rightarrow x+5=7\)
\(\Rightarrow x=2\)
\(\left(x+5\right)+3=9\)
\(=x+5+3=9\)
\(\Rightarrow x+8=9\)
\(\Rightarrow x=1\)
\(\left(x-1\right)-4=7\)
\(\Rightarrow x-1-4=7\)
\(\Rightarrow x-5=7\)
\(\Rightarrow x=12\)
\(4-\left(6-x\right)=1\)
\(\Rightarrow4-6-x=1\)
\(\Rightarrow-2-x=1\)
\(\Rightarrow x=-3\)

a)[(\(\frac{36}{41}\): \(\frac{9}{41}\)) : (\(\frac{14}{21}\):\(\frac{7}{21}\)) x \(\frac{2}{5}\)]
=[ 4 : 2 x \(\frac{2}{5}\)]
=\(\frac{4}{5}\)
b) (\(\frac{1}{2}\)- \(\frac{1}{4}\)+\(\frac{1}{5}\)) : (\(\frac{1}{2}\)+ \(\frac{1}{4}\)'- \(\frac{1}{5}\))
=\(\frac{9}{20}\): \(\frac{11}{20}\)
=\(\frac{9}{11}\)
( Mình tính luôn cho nó nhanh phần cuối cùng nhá)
=\(\frac{4}{5}\): \(\frac{3}{5}\)
=\(\frac{4}{3}\)
`1/5 . (1/2-1/3):(-9/10) + 7/3`
`=1/5 . (3/6-2/6) : (-9/10) + 7/3`
`=1/5 . 1/6 : (-9/10) + 7/3`
`=1/5 . 1/6 xx (-10/9) + 7/3`
`=1/30 xx (-10/9) + 7/3`
`=-1/27 + 7/3`
`=-1/27 + 63/27`
`=62/27`
Lời giải:
$\frac{1}{5}.(\frac{1}{2}-\frac{1}{3}):(\frac{-9}{10})+\frac{7}{3}$
$=\frac{1}{5}.\frac{1}{6}.\frac{10}{-9}+\frac{7}{3}$
$=\frac{1}{30}.\frac{10}{-9}+\frac{7}{3}=\frac{-1}{27}+\frac{63}{27}$
$=\frac{62}{27}$