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b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8
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\(\frac{24}{36}:\frac{8}{9}=\frac{24}{36}\cdot\frac{9}{8}=\frac{24\cdot9}{36\cdot8}=\frac{216}{288}=\frac{3}{4}\)
\(\frac{32}{45}-\frac{7}{30}=\frac{64}{90}-\frac{21}{90}=\frac{43}{90}\)
\(\frac{3}{10}+\frac{4}{7}+\frac{6}{14}+\frac{4}{20}=\frac{42}{140}+\frac{80}{140}+\frac{60}{140}+\frac{28}{140}=\frac{210}{140}=\frac{3}{2}\)
\(\frac{17}{25}\cdot\frac{11}{28}+\frac{34}{50}\cdot\frac{17}{28}=\frac{187}{700}+\frac{289}{700}=\frac{476}{700}=\frac{17}{25}\)
\(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{11\cdot12}=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{11}-\frac{1}{12}=\frac{1}{3}-\frac{1}{12}=\frac{1}{4}\)
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\(\frac{3}{4}.\frac{5}{7}=\frac{3.5}{4.7}=\frac{15}{28}\)
\(\frac{15}{28}:\frac{5}{7}=\frac{15.7}{28.5}=\frac{105}{140}=\frac{21}{28}\)
\(\frac{1}{7}.\frac{1}{5}=\frac{1}{7.5}=\frac{1}{35}\)
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số số hạng là :
( 28 - 1 ) : 3 + 1 = 10 ( số )
tổng là :
( 28 + 1 ) x 10 : 2 = 145
Đáp số : 145
số số hạng là
(28- 1 ) :3 + 1 = 10 ( số )
số cặp số là
10:2 = 5 ( cặp )
giá trị 1 cặp là
28+1 = 29
tổng là
29 x 5 = 145
đap số 145
h nhé
thanks
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\(a)9+\frac{24}{25}=\frac{9\cdot25+24}{25}=\frac{249}{25}\)
\(b)\frac{1}{20}+\frac{1}{4}+\frac{2}{5}=\frac{1}{20}+\frac{5}{20}+\frac{8}{20}=\frac{1+5+8}{20}=\frac{14}{20}=\frac{7}{10}\)
\(c)\frac{7}{12}+4=\frac{7}{12}+\frac{4}{1}=\frac{7+48}{12}=\frac{55}{12}\)
\(d)10+\frac{9}{8}=\frac{10}{1}+\frac{9}{8}=\frac{80+9}{8}=\frac{89}{8}\)
\(e)\frac{1}{4}+\frac{2}{25}+\frac{9}{100}=\frac{25}{100}+\frac{8}{100}+\frac{9}{100}=\frac{25+8+9}{100}=\frac{42}{100}=\frac{21}{50}\)
Còn 3 câu làm tương tự
Ba câu còn lại mình làm luôn :D
\(f)\frac{28}{90}+6=\frac{14}{45}+6=\frac{14}{45}+\frac{6}{1}=\frac{14+270}{45}=\frac{284}{45}\)
\(g)\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}=(\frac{3}{7}+\frac{4}{7})+\frac{4}{9}+\frac{4}{11}=1+\frac{4}{9}+\frac{4}{11}\)
\(=\frac{7}{7}+\frac{4}{9}+\frac{4}{11}=\frac{693+308+252}{693}=\frac{1253}{693}=\frac{179}{99}\)
\(h)\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}=(\frac{1}{8}+\frac{3}{8})+(\frac{1}{12}+\frac{5}{12})=\frac{4}{8}+\frac{6}{12}=\frac{1}{2}+\frac{1}{2}=1\)
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( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ...+ ! x + 28 ) = 155
( x + x + x + ....+ x ) + ( 1 + 4 + 7 + .. + 28 ) = 155
10.x + ( 28 - 1 : 3 + 1 ) : 2 . ( 28 + 1) = 155
10 . x + 145 = 155
10 . x = 155 - 145
10.x = 10
x = 10 : 10
x = 1
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\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+...+\left(x+28\right)=155\)
\(\Rightarrow\left(x+x+x+...+x\right)+\left(1+4+7+...+28\right)=155\)
\(\Rightarrow10x+\frac{\left(28+1\right).10}{2}=155\)
\(\Rightarrow10x+145=155\)
\(\Rightarrow10x=155-145\)
\(\Rightarrow10x=10\)
\(\Rightarrow x=1\)
( X + 1 ) + ( X + 4 ) + ( X + 7 ) + .... + ( X + 28 ) = 155
( x + x + ... + x ) + ( 1 + 4 + 7 + 28 ) = 155
28.x + 145 = 155
=> 28.x = 10
=> x = 5/14
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\(3+\frac{35}{21}+6=\frac{3}{1}+\frac{35}{21}+\frac{6}{1}=\frac{63}{21}+\frac{35}{21}+\frac{126}{21}=\frac{224}{21}\)
\(\frac{3}{8}+\frac{1}{5}+7=\frac{3}{8}+\frac{1}{5}+\frac{7}{1}=\frac{15}{40}+\frac{8}{40}+\frac{280}{40}=\frac{303}{40}\)
\(\frac{14}{28}+\frac{3}{4}+2=\frac{2}{4}+\frac{3}{4}+2=\frac{2}{4}+\frac{3}{4}+\frac{2}{1}=\frac{2}{4}+\frac{3}{4}+\frac{8}{4}=\frac{13}{4}\)
\(\frac{3}{5}+\frac{1}{4}+\frac{2}{3}=\frac{36}{60}+\frac{15}{60}+\frac{40}{60}=\frac{91}{60}\)