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1. ( -37 ) + 14 + 26 + 37
=(-37+37)+(14+26)
=0+30
=30
2. ( -24 )+ 6 + 10 + 24
=(-24+24)+(6+10)
=0+16
=16
3. 15 + 23 + ( -25 ) + ( -32 )
=[15+(-25)]+[23+(-32)]
=-10+(-9)
=-19
4. 60 + 33 + ( -50 ) + ( -33 )
=[60+(-50)]+[33+(-33)]
=10+0
=10
5. (- 16 ) + ( -209 ) + ( -14 ) + 209
=[-16+(-14)]+(-209+209)
=-30+0
=-30
6. (- 12 ) + ( -13 ) + 36 + ( -11 )
=[-12+(-11)]+(-13+36)
=-23+23
=0
7. - 16 + 24 - 16 - 34
=(24-34)-16-16
=-10-16-16
=-42
8. 25 + 37 - 48 - 25 - 37
=(25-25)+(37-37)-48
=0+0-48
=-48
9. 2575 + 37 - 48 - 25 - 37
=(2575-25)+(37-37)
=2550+0
=2550
10. 34 + 35 + 36 + 37 - 14 - 15 - 16 - 17
=(34-14)+(35-15)+(36-16)+(37-17)
=20+20+20+20
=20.4
=80
cái này giống BTVN của mk,nhưng dễ mak,tự làm đc mak
cố lên
Giải:
\(\left(\dfrac{1}{4}+\dfrac{11}{9}\right):\dfrac{34}{5}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right):\dfrac{34}{5}\)
\(=\left(\dfrac{1}{4}+\dfrac{11}{9}\right).\dfrac{5}{34}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\)
\(=\left[\left(\dfrac{1}{4}+\dfrac{11}{9}\right)+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right)\right].\dfrac{5}{34}\)
\(=\left[\dfrac{1}{4}+\dfrac{11}{9}-\dfrac{2}{9}+\dfrac{29}{4}\right].\dfrac{5}{34}\)
\(=\left[\dfrac{9}{9}+\dfrac{30}{4}\right].\dfrac{5}{34}\)
\(=\left[1+\dfrac{15}{2}\right].\dfrac{5}{34}\)
\(=\dfrac{17}{2}.\dfrac{5}{34}\)
\(=\dfrac{5}{4}\)
Vậy ...
\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\left(\frac{5}{4}-\frac{2}{3}\right)\)\(\times\)\(\left(-3\right)^2\)\(+\)\(\frac{5}{9}\)\(\times\)\(30\%\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\frac{7}{12}\)\(\times\)\(9\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{1}{6}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{1}{6}\)\(+\)\(\frac{7}{3}\)
\(=\)\(\frac{-2}{3}\)\(+\)\(\frac{7}{3}\)
\(=\)\(\frac{5}{3}\)
42 - 9 ( 34 - 55 : 53 )
= 42 - 9 ( 34 - 52 )
= 42 - 9 ( 34 - 25 )
= 42 - 9 . 9
= 42 - 81
= 16 - 81
= 16 + ( - 81 )
= - 65
= - 65 nha bn.
Phạm Thị Lam làm đúng rùi đó !
Chính xác 100 % Luôn bạn .
Sửa đề P = \(\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+...+\frac{11}{5^{11}}\)CM P < 5/16
=> 5P = \(1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{11}{5^{10}}\)
Lấy 5P trừ P theo vế ta có
5P - P = \(\left(1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{11}{5^{10}}\right)-\left(\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+...+\frac{11}{5^{11}}\right)\)
4P = \(1+\left(\frac{2}{5}-\frac{1}{5}\right)+\left(\frac{3}{5^2}-\frac{2}{5^2}\right)+...+\left(\frac{11}{5^{10}}-\frac{10}{5^{10}}\right)-\frac{11}{5^{11}}\)
4P = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}-\frac{11}{5^{11}}\)
Đặt Q = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}\)
=> 5Q \(=5+1+\frac{1}{5}+...+\frac{1}{5^9}\)
Lấy 5Q trừ Q theo vế ta có
5Q - Q = \(\left(5+1+\frac{1}{5}+...+\frac{1}{5^9}\right)-\left(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}\right)\)
4Q \(=5-\frac{1}{5^{10}}\)
=> Q\(=\frac{5}{4}-\frac{1}{5^{10}.4}\)
Khi đó 4P = \(\frac{5}{4}-\frac{1}{5^{10}.4}-\frac{11}{5^{11}}\)
=> P = \(\frac{5}{16}-\frac{1}{5^{10}.16}-\frac{11}{5^{11}.4}\)
\(=\frac{5}{16}-\frac{1}{5^{10}}\left(\frac{1}{16}-\frac{11}{5.4}\right)< \)\(\frac{5}{16}\)
Bài làm:
Ta có: \(\frac{1}{5^2}+\frac{2}{5^2}+\frac{3}{5^2}+...+\frac{11}{5^2}\)
\(=\frac{1+2+3+...+11}{5^2}=\frac{\left(1+11\right).11:2}{5^2}=\frac{66}{25}>1>\frac{1}{16}\)
\(\Rightarrow P>\frac{1}{16}\)
=> Đề sai
1)\(79-5\left(11-x\right)=34\)
\(\Rightarrow79-55+5x=34\)
\(\Rightarrow24+5x=34\)
\(\Rightarrow5x=-10\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
2)\(32+2\left(7-x\right)=40\)
\(\Rightarrow32+14-2x=40\)
\(\Rightarrow46-2x=40\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
3)\(\left(166-2x\right).8^9=2.8^{11}\)
\(\Rightarrow\left(83-x\right).2.8^9=2.8^{11}\)
\(\Rightarrow83-x=8^3\)
\(\Rightarrow83-x=512\)
\(\Rightarrow x=-429\)
Vậy \(x=-429\)
4)\(5^2.x-2^3.x=51\)
\(\Rightarrow x\left(5^2-2^3\right)=51\)
\(\Rightarrow x\left(25-8\right)=51\)
\(\Rightarrow17x=51\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
5)\(3^x+4.3^x=5.3^7\)
\(\Rightarrow3^x\left(1+4\right)=5.3^7\)
\(\Rightarrow5.3^x=5.3^7\)
\(\Rightarrow3^x=3^7\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
6)\(7.2^x-2^x=6.32\)
\(\Rightarrow2^x\left(7-1\right)=6.2^5\)
\(\Rightarrow6.2^x=6.2^5\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
7)\(15^{3-x}=225\)
\(\Rightarrow15^{3-x}=15^2\)
\(\Rightarrow3-x=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
8)\(4.5^x-3=97\)
\(\Rightarrow4.5^x=100\)
\(\Rightarrow5^x=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
9)\(171-3.2^x=123\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
10)\(180-4.x^5=32\)
\(\Rightarrow4.x^5=148\)
\(\Rightarrow x^5=37\)//Đề có lỗi không ???
\(\left[\frac{1}{4}+\frac{11}{9}\right]:\frac{34}{5}+\left[-\frac{2}{9}+\frac{39}{4}\right]:\frac{34}{?}\)
Bạn còn thiếu j không?
thằng nào nói mẫu số sai vì thằng đó quá bá đạo