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6 tháng 5 2019

\(\left[\frac{1}{4}+\frac{11}{9}\right]:\frac{34}{5}+\left[-\frac{2}{9}+\frac{39}{4}\right]:\frac{34}{?}\)

Bạn còn thiếu j không?

6 tháng 5 2019

thằng nào nói mẫu số sai vì thằng đó quá bá đạo

10 tháng 3 2020

1. ( -37 ) + 14 + 26 + 37

=(-37+37)+(14+26)

=0+30

=30

2. ( -24 )+ 6 + 10 + 24

=(-24+24)+(6+10)

=0+16

=16

3. 15 + 23 + ( -25 ) + ( -32 )

=[15+(-25)]+[23+(-32)]

=-10+(-9)

=-19

4. 60 + 33 + ( -50 ) + ( -33 )

=[60+(-50)]+[33+(-33)]

=10+0

=10

5. (- 16 ) + ( -209 ) + ( -14 ) + 209

=[-16+(-14)]+(-209+209)

=-30+0

=-30

6.  (- 12 ) + ( -13 ) + 36 + ( -11 )

=[-12+(-11)]+(-13+36)

=-23+23

=0

7. - 16  + 24 - 16 - 34

=(24-34)-16-16

=-10-16-16

=-42

8.  25 + 37 - 48 - 25 - 37

=(25-25)+(37-37)-48

=0+0-48

=-48

9. 2575 + 37 - 48 - 25 - 37

=(2575-25)+(37-37)

=2550+0

=2550

10. 34 + 35 + 36 + 37 - 14 - 15 - 16 - 17

=(34-14)+(35-15)+(36-16)+(37-17)

=20+20+20+20

=20.4

=80

cái này giống BTVN của mk,nhưng dễ mak,tự làm đc mak

  cố lên

20 tháng 3 2018

Giải:

\(\left(\dfrac{1}{4}+\dfrac{11}{9}\right):\dfrac{34}{5}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right):\dfrac{34}{5}\)

\(=\left(\dfrac{1}{4}+\dfrac{11}{9}\right).\dfrac{5}{34}+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right).\dfrac{5}{34}\)

\(=\left[\left(\dfrac{1}{4}+\dfrac{11}{9}\right)+\left(\dfrac{-2}{9}+\dfrac{29}{4}\right)\right].\dfrac{5}{34}\)

\(=\left[\dfrac{1}{4}+\dfrac{11}{9}-\dfrac{2}{9}+\dfrac{29}{4}\right].\dfrac{5}{34}\)

\(=\left[\dfrac{9}{9}+\dfrac{30}{4}\right].\dfrac{5}{34}\)

\(=\left[1+\dfrac{15}{2}\right].\dfrac{5}{34}\)

\(=\dfrac{17}{2}.\dfrac{5}{34}\)

\(=\dfrac{5}{4}\)

Vậy ...

31 tháng 7 2021

\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\left(\frac{5}{4}-\frac{2}{3}\right)\)\(\times\)\(\left(-3\right)^2\)\(+\)\(\frac{5}{9}\)\(\times\)\(30\%\)

\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\frac{7}{12}\)\(\times\)\(9\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)

\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)

\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{1}{6}\)

\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{1}{6}\)\(+\)\(\frac{7}{3}\)

\(=\)\(\frac{-2}{3}\)\(+\)\(\frac{7}{3}\)

\(=\)\(\frac{5}{3}\)

3 tháng 1 2019

   42 - 9 ( 34 - 5: 53 )

= 4- 9 ( 34 - 52 )

= 42 - 9 ( 34 - 25 )

= 42 - 9 . 9

= 42 - 81

= 16 - 81

= 16 + ( - 81 )

= - 65

= - 65 nha bn.

Phạm Thị Lam làm đúng rùi đó !

Chính xác 100 % Luôn bạn .

23 tháng 7 2020

Sửa đề  P = \(\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+...+\frac{11}{5^{11}}\)CM P < 5/16

=> 5P = \(1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{11}{5^{10}}\) 

Lấy 5P trừ P theo vế ta có

5P - P = \(\left(1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{11}{5^{10}}\right)-\left(\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+...+\frac{11}{5^{11}}\right)\)

4P = \(1+\left(\frac{2}{5}-\frac{1}{5}\right)+\left(\frac{3}{5^2}-\frac{2}{5^2}\right)+...+\left(\frac{11}{5^{10}}-\frac{10}{5^{10}}\right)-\frac{11}{5^{11}}\)

4P = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}-\frac{11}{5^{11}}\)

Đặt Q = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}\)

=> 5Q \(=5+1+\frac{1}{5}+...+\frac{1}{5^9}\)

Lấy 5Q trừ Q theo vế ta có

5Q - Q = \(\left(5+1+\frac{1}{5}+...+\frac{1}{5^9}\right)-\left(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{10}}\right)\)

4Q \(=5-\frac{1}{5^{10}}\)

=> Q\(=\frac{5}{4}-\frac{1}{5^{10}.4}\)

Khi đó 4P = \(\frac{5}{4}-\frac{1}{5^{10}.4}-\frac{11}{5^{11}}\)

=> P = \(\frac{5}{16}-\frac{1}{5^{10}.16}-\frac{11}{5^{11}.4}\)

\(=\frac{5}{16}-\frac{1}{5^{10}}\left(\frac{1}{16}-\frac{11}{5.4}\right)< \)\(\frac{5}{16}\)

23 tháng 7 2020

Bài làm:

Ta có: \(\frac{1}{5^2}+\frac{2}{5^2}+\frac{3}{5^2}+...+\frac{11}{5^2}\)

\(=\frac{1+2+3+...+11}{5^2}=\frac{\left(1+11\right).11:2}{5^2}=\frac{66}{25}>1>\frac{1}{16}\)

\(\Rightarrow P>\frac{1}{16}\)

=> Đề sai

1)\(79-5\left(11-x\right)=34\)

\(\Rightarrow79-55+5x=34\)

\(\Rightarrow24+5x=34\)

\(\Rightarrow5x=-10\)

\(\Rightarrow x=-2\)

Vậy \(x=-2\)

2)\(32+2\left(7-x\right)=40\)

\(\Rightarrow32+14-2x=40\)

\(\Rightarrow46-2x=40\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

Vậy \(x=3\)

3)\(\left(166-2x\right).8^9=2.8^{11}\)

\(\Rightarrow\left(83-x\right).2.8^9=2.8^{11}\)

\(\Rightarrow83-x=8^3\)

\(\Rightarrow83-x=512\)

\(\Rightarrow x=-429\)

Vậy \(x=-429\)

4)\(5^2.x-2^3.x=51\)

\(\Rightarrow x\left(5^2-2^3\right)=51\)

\(\Rightarrow x\left(25-8\right)=51\)

\(\Rightarrow17x=51\)

\(\Rightarrow x=3\)

Vậy \(x=3\)

5)\(3^x+4.3^x=5.3^7\)

\(\Rightarrow3^x\left(1+4\right)=5.3^7\)

\(\Rightarrow5.3^x=5.3^7\)

\(\Rightarrow3^x=3^7\)

\(\Rightarrow x=7\)

Vậy \(x=7\)

6)\(7.2^x-2^x=6.32\)

\(\Rightarrow2^x\left(7-1\right)=6.2^5\)

\(\Rightarrow6.2^x=6.2^5\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy \(x=5\)

7)\(15^{3-x}=225\)

\(\Rightarrow15^{3-x}=15^2\)

\(\Rightarrow3-x=2\)

\(\Rightarrow x=1\)

Vậy \(x=1\)

8)\(4.5^x-3=97\)

\(\Rightarrow4.5^x=100\)

\(\Rightarrow5^x=25\)

\(\Rightarrow5^x=5^2\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

9)\(171-3.2^x=123\)

\(\Rightarrow3.2^x=48\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

Vậy \(x=4\)

10)\(180-4.x^5=32\)

\(\Rightarrow4.x^5=148\)

\(\Rightarrow x^5=37\)//Đề có lỗi không ???