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19 tháng 4 2020

ta có:x/5=21x/105,-13/15=-91/105,-13/21=-65/105

=>-91/105<21x/105<-65/105

=>-91<21x<-65

=>21x thuôc{-90;-89;-88;-87;-86;-85;........;-60;-61;-62;-63}

=>x thuộc{-4;-3}

Vậy x = -4 hoặc x=-3

\(\frac{-13}{15}< \frac{y}{5}< \frac{-13}{21}\)

\(\frac{-13}{15}=\frac{-13.7}{15.7}=\frac{-91}{105}\)

\(\frac{y}{5}=\frac{21.y}{5.21}=\frac{21y}{105}\)

\(\frac{-13}{21}=\frac{-13.5}{21.5}=\frac{-65}{105}\)

=>\(\frac{-91}{105}< \frac{21y}{105}< \frac{-65}{105}\)

=> \(-91< 21y< -65\)

=> \(y=-4\)

Vì 21.(-4)=-84 (-91<-84<-65)

=>\(y=-4\)

Chúc bạn học tốt!

23 tháng 7 2019

có \(-\frac{13}{15}< \frac{y}{5}< -\frac{13}{21}\)

\(\Leftrightarrow-\frac{91}{105}< \frac{21y}{105}< -\frac{65}{105}\)

\(\Rightarrow\hept{\begin{cases}-91< 21y< -65\\21y⋮21\end{cases}}\)

vì y thuộc Z

\(\Rightarrow21y=-84\)

\(\Rightarrow y=-4\)

3 tháng 4 2017

1) x - 2 = -6

x = -6 + 2

x = -4

2) -5 . x - ( -3 ) =13

-5 . x = 13 + ( -3 )

-5 . x = 10

x = 10 : ( -5 )

x = -2

5 tháng 2 2020

a, 43 + ( 9 - 21 ) = 317 - ( x + 317 )

   43 + ( -12 ) = 317 - x - 317

   43 - 12 = 317 - 317 - x

   -x = 31

   x = -31

b, (15-x) + (x-12) = 7- (-5 + x)

    15-x+x-12 = 7+5-x

     15-12 = 12-x

     3 = 12-x

     x =  12-3

     x = 9

c, x - { 57- [42+ (-23 - x)]} = 13- {47+ [25- (32-x)]}

   x - [57- (42-23-x)] = 13- [47+ (25-32+x)]

   x - [57- (19-x)] = 13- [47+ (x-7)]

   x - (57-19+x) = 13- (47+x-7)

   x - (38+x) = 13- (40+x)

   x-38-x = 13-40-x

   x = 13-40+38

   x = 11

28 tháng 2 2020

a , 43 + ( 9 - 21 ) = 317 - ( x + 317 )

b , ( 15 - x ) + ( x - 12 ) = 7 - ( -5 + x )

c , x - { 57 - [ 42 + ( -23 - x )]} = 13 - { 47 + [ 25 - ( 32 - x )]}

d , -7 + | x - 4 | = -3

4 tháng 2 2020

a) \(43+\left(9-21\right)=317-\left(x+317\right)\\ 43+9-21=317-x-317\\ 52-21=\left(317-317\right)-x\\ 31=-x\\ x=-31\)Vậy x = -31

b) \(\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\\ 15-x+x-12=7+5-x\\ \left(x-x\right)+\left(15-12\right)=12-x\\ 3=12-x\\ x=9\)Vậy x = 9

c) \(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\\ x-\left\{57-\left[42+\left(-23\right)-x\right]\right\}=13-\left\{47+\left[25-32+x\right]\right\}\\ x-\left\{57-42+23+x\right\}=13-\left\{47+25-32+x\right\}\\ x-57+42-23-x=13-47-25+32-x\\ -57+42-23=-34-25+32-x\\ -15-23=-59+32-x\\ -38=-27-x\\ x=11\)Vậy x = 11

d) \(-7+\left|x-4\right|=-3\\ \left|x-4\right|=4\\ \Rightarrow\left[{}\begin{matrix}x-4=4\\x-4=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=8\\x=0\end{matrix}\right.\)Vậy \(x\in\left\{8;0\right\}\)

e) \(13-\left|x+5\right|=13\\ \left|x+5\right|=0\\ \Rightarrow x+5=0\\ \Rightarrow x=-5\)Vậy x = -5

g) \(\left|x-10\right|-\left(-12\right)=4\\ \left|x-10\right|=-8\\ \Rightarrow x\in\varnothing\left(\text{vì }\left|x-10\right|\ge0\text{với mọi }x\right)\)Vậy \(x\in\varnothing\)

h) \(\left|x+2\right|< 5\\ 0\le\left|x+2\right|< 5\\ \Rightarrow\left|x+2\right|\in\left\{1;2;3;4\right\}\\ \Rightarrow x+2\in\left\{1;-1;2;-2;3;-3;4;-4\right\}\\ \Rightarrow x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)Vậy \(x\in\left\{-1;-3;0;-4;1;-5;2;-6\right\}\)

5 tháng 2 2020

a) 43+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−3143+(9−21)=317−(x+317)43+9−21=317−x−31752−21=(317−317)−x31=−xx=−31Vậy x = -31

b) (15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9(15−x)+(x−12)=7−(−5+x)15−x+x−12=7+5−x(x−x)+(15−12)=12−x3=12−xx=9Vậy x = 9

c) x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11x−{57−[42+(−23−x)]}=13−{47+[25−(32−x)]}x−{57−[42+(−23)−x]}=13−{47+[25−32+x]}x−{57−42+23+x}=13−{47+25−32+x}x−57+42−23−x=13−47−25+32−x−57+42−23=−34−25+32−x−15−23=−59+32−x−38=−27−xx=11Vậy x = 11

d) −7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0−7+|x−4|=−3|x−4|=4⇒[x−4=4x−4=−4⇒[x=8x=0Vậy x∈{8;0}x∈{8;0}

e) 13−|x+5|=13|x+5|=0⇒x+5=0⇒x=−513−|x+5|=13|x+5|=0⇒x+5=0⇒x=−5Vậy x = -5

g) |x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)|x−10|−(−12)=4|x−10|=−8⇒x∈∅(vì |x−10|≥0với mọi x)Vậy x∈∅x∈∅

h) |x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}|x+2|<50≤|x+2|<5⇒|x+2|∈{1;2;3;4}⇒x+2∈{1;−1;2;−2;3;−3;4;−4}⇒x∈{−1;−3;0;−4;1;−5;2;−6}Vậy x∈{−1;−3;0;−4;1;−5;2;−6}

24 tháng 1 2017

1)x=-30

2)x=-81

3)x=4

4)x=62

5)x=6

6)-13

7)-13

8)-31

9)x=-6;0;6;12

tk minh nha

25 tháng 1 2017

bạn không có lời giải

27 tháng 7 2023

có đúng ko