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Ta có :
\(\left(\frac{16}{25}\right)^{10}=\left(\frac{4^2}{5^2}\right)^{10}=\left(\frac{4}{5}\right)^{2.10}=\left(\frac{4}{5}\right)^{20}\)
\(\left(\frac{3}{7}\right)^{40}=\left(\frac{3}{7}\right)^{2.20}=\left(\frac{3^2}{7^2}\right)^{20}=\left(\frac{9}{49}\right)^{20}\)
Vì 20 = 20 và \(\frac{4}{5}>\frac{9}{49}\)nên \(\left(\frac{4}{5}\right)^{20}>\left(\frac{9}{49}\right)^{20}\)
Vậy \(\left(\frac{16}{25}\right)^{10}>\left(\frac{3}{7}\right)^{40}\)
a) 5200 = (52)100 = 25100
3453= 3400 x 353 = ( 34)100 x 353 = 81100 x 353
Ta thấy 81100 > 25100 => 81100 x 353 > 25100
Vậy 3453 > 5200
b) 2164= 2160 x 24 = (24)40 x24 = 1640 x 24
Ta thấy: 1640 > 1340 => 1640 x 24 > 1340
Vậy 2164 > 1340
Nhớ k mik nha
\(\left(-32\right)^9=-\left(2^5\right)^9=-\left(2^{45}\right)\)
\(\left(-16\right)^{13}=-\left(2^4\right)^{13}=-\left(2^{52}\right)\)
vì -2^45>-2^52hay -16^13>-32^9
b, Bài giải
\(\left(-32\right)^9=\left(-16\cdot2\right)^9=\left(-16\right)^9\cdot2^9\)
\(\left(-16\right)^{13}=\left(-16\right)^9\cdot\left(-16\right)^4=\left(-16\right)^9\cdot\left[\left(-2\right)^4\right]^4=\left(-16\right)^9\cdot\left(-2\right)^{16}=\left(-16\right)^9\cdot2^{16}\)
Vì \(2^9< 2^{16}\) nên \(\left(-32\right)^9>\left(-16\right)^{13}\)
Ta có 13x = \(\frac{13^{17}+13}{13^{17}+1}=1+\frac{12}{13^{17}+1}\)
13y = \(\frac{13^{16}+13}{13^{16}+1}=1+\frac{12}{13^{16}+1}\)
Vì 1317 + 1 > 1316 + 1
=> \(\frac{1}{13^{17}+1}< \frac{1}{13^{16}+1}\)
=> \(\frac{12}{13^{17}+1}< \frac{12}{13^{16}+1}\)
=> \(1+\frac{12}{13^{17}+1}< 1+\frac{12}{13^{16}+1}\)
=> 13x < 13y
=> x < y
Vậy x < y
a) 7^13 = 7.7^12 = 7.(7^2)^6 = 7. 49^6 > 39^6
b) 9^36 = 9^4.9^32 = 9^4. (9^2)^16 = 9^4.81^16 > 79^16
Ta có: 9/16=27/48
: -13/-24=13/24=26/48
Mà:27>26=>27/48>26/48
Nên 9/16>-13/-24
Ta có:
\(A=\frac{13^{15}+1}{13^{16}+1}\Rightarrow13A=\frac{13^{16}+13}{13^{16}+1}=\frac{13^{16}+1+12}{13^{16}+1}=1+\frac{12}{13^{16}+1}\)
\(B=\frac{13^{16}+1}{13^{17}+1}\Rightarrow13B=\frac{13^{17}+13}{13^{17}+1}=\frac{13^{17}+1+12}{13^{17}+1}=1+\frac{12}{13^{17}+1}\)
Ta thấy:
\(13^{16}+1< 13^{17}+1\)
\(\Rightarrow\frac{12}{13^{16}+1}>\frac{12}{13^{17}+1}\)
\(\Rightarrow1+\frac{12}{13^{16}+1}>1+\frac{12}{13^{17}+1}\)
hay \(A>B\)
Vậy \(A>B.\)
ta có : \(\left(-\frac{1}{2}\right)^{500}=\left[\left(-\frac{1}{2}\right)^5\right]^{100}=\left(-\frac{1}{32}\right)^{100}\)
=> \(\left(-\frac{1}{16}\right)^{100}< \left(-\frac{1}{32}\right)^{100}\)
<=> \(\left(-\frac{1}{16}\right)^{100}< \left(-\frac{1}{2}\right)^{500}\)
câu b cũng tương tự nha tất cả đưa về cơ số là -2
Ta có:
\(\dfrac{-13}{40}=\dfrac{-13.2}{40.2}=\dfrac{-26}{80}\)
\(\dfrac{-3}{16}=\dfrac{-3.5}{16.5}=\dfrac{-15}{80}\)
Vì 26 > 15
nên \(\dfrac{-26}{80}< \dfrac{-15}{80}\)
Hay \(\dfrac{-13}{40}< \dfrac{-3}{16}\)
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