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Ta có: \(13\cdot\left(-47\right)-53\cdot13\)
\(=13\cdot\left(-47-53\right)\)
\(=13\cdot\left(-100\right)=-1300\)
Ta có: \(27\cdot\left(-67\right)+33\cdot\left(-27\right)\)
\(=27\cdot\left(-67\right)-33\cdot27\)
\(=27\left(-67-33\right)\)
\(=27\cdot\left(-100\right)=-2700\)
Ta có: \(-49\cdot65+36\cdot\left(-49\right)+49\)
\(=-49\cdot65+\left(-49\right)\cdot36+\left(-49\right)\cdot\left(-1\right)\)
\(=-49\cdot\left(65+36-1\right)\)
\(=-49\cdot100=-4900\)
Ta có: \(136\cdot\left(-47\right)+36\cdot47\)
\(=\left(-136\right)\cdot47+36\cdot47\)
\(=47\cdot\left(-136+36\right)\)
\(=47\cdot\left(-100\right)=-4700\)
Ta có: \(\left(-48\right)\cdot72+36\cdot\left(-304\right)\)
\(=-96\cdot36+36\cdot\left(-304\right)\)
\(=36\cdot\left(-96-304\right)\)
\(=36\cdot\left(-400\right)=-14400\)
a) – 3 < x < 1 => x = 0
b) 0 < x < 3 => x ∈ {1;2}
c) -3 < x < 8 => x ∈ {0;1;2;3;4;5;6;7}
72-7.(13-x)=14
=>7.(13-x)=72-14
=>7.(13-x)=58
=>13-x=58:7
=>13-x=\(\dfrac{58}{7}\)
\(=>x=13-\dfrac{58}{7}\)
\(=>x=\dfrac{33}{7}\)
Vậy ................
\(72-7\left(13-x\right)=14\)
\(7\left(13-x\right)=58\)
\(13-x=\dfrac{58}{7}\)
\(x=13-\dfrac{58}{7}\)
\(x=\dfrac{91}{7}-\dfrac{58}{7}\)
\(x=\dfrac{33}{7}\)
`72-7(13-x)=14`
`=>7(13-x)=72-14`
`=>7(13-x)=58`
`=>13-x=58:7`
`=>13-x=58/7`
`=>x=13-58/7`
`=>x=33/7`
(3.x-72).372=13.69-39.23
(3.x-72).372=897-897
(3.x-72).372=0
3.x-72=0:372
3.x-72=0
3.x=72+0=72
x=72:3
x=24
chúc bạn học tốt nha
a,280: (7 + 3 : x ) = 4
(7 + 3 : x ) = 280:4
( 7+ 3: x) =70
3 : x = 70-7
3:x=63
x=63.3
x= 189
b,(x+5).19:13=57
(x+5).19 =57.13
(x+5).19 =741
(x+5) =741:19
(x+5) =39
x=39-5
x = 34
c,6.(28-8.x)=72
(28-8.x)=72:6
(28-8.x)=12
8x=28-12
8x=16
x=16:8
X=2
x=8
[(-13).(-13)] .x-72=16.10.x
\(\Leftrightarrow169x-72=160x\)
\(\Leftrightarrow9x=72\)
\(\Leftrightarrow x=8\)