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\(2\frac{4}{3}+\frac{4}{12}=\frac{2.3+4}{3}+\frac{4}{12}=\frac{10}{3}+\frac{4}{12}=\frac{40}{12}+\frac{4}{12}=\frac{44}{12}=\frac{11}{3}\)
\(2\frac{4}{3}=\frac{10}{3}\)
\(\frac{10}{3}+\frac{4}{12}=\frac{120}{36}+\frac{12}{36}\)
\(=\frac{132}{36}=\frac{22}{6}=\frac{11}{3}\)
2\(\frac{2}{12}\)+ X = \(\frac{5}{7}\)+ \(\frac{8}{12}\)
\(\frac{13}{6}\)+ X=\(\frac{29}{21}\)
X= \(\frac{29}{21}\)- \(\frac{13}{6}\)
X=\(\frac{-11}{14}\)
\(|2^2_{12}\)\(+x=\frac{5}{7}+\frac{8}{12}\)
\(2+x=\frac{5}{7}+\frac{1}{2}\)
\(2+x=\frac{17}{14}\)
\(x=\frac{17}{14}-2\)
\(x=\frac{-11}{14}\)
\(12+\frac{4}{12}\cdot6=12+\frac{1}{3}\cdot6=12+\frac{6}{3}=12+2=14\)
a, cách 1 : 7/11 : 3/5 + 4/11 : 3/5 b, cách 1 : [ 6,24 + 1,26 ] : 0,75
=[ 7/11 + 4/11 ] : 3/5 = 7,5 : 0,75
= 1 : 3/5 = 10
= 5/3 cách 2 : [ 6,24 + 1,26 ] : 0,75
cách 2 :7/11 : 3/5 + 4/11 : 3/5 = 6,24 : 0,75 + 1,26 : 0,75
=35/33 + 20/33 = 8,32 + 1,68
=55/33 = 10
=5/3
\(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
= ( \(\frac{7}{11}+\frac{4}{11}\)) : \(\frac{3}{5}\)
= 1 : \(\frac{3}{5}\)
= \(\frac{5}{3}\)
\(9\frac{5}{34}-12+5\)
\(9\frac{5}{34}=\frac{311}{34}\)
\(\Rightarrow9\frac{5}{34}-12+5\)
\(=\frac{311}{34}-12+5\)
\(=-\frac{97}{34}+5\)
\(=\frac{73}{34}\)
\(12\frac{4}{5}\)=\(\frac{64}{5}\).
Ta có :
\(\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)
\(12\frac{4}{5}+\frac{4}{5}=\frac{64}{5}+\frac{4}{5}=\frac{68}{5}\)