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a,x=-2,-2,0,1
b, x-18=16x3
x-18=48 suy ra x = 66
c, 3x(x+4)=128-23
3x(x+4)=105
x(x+4)=105:3=35
x.x=x.4
x^2=4
x=2
a,=>x=(-2)-1;0;1
b,x-18=16.3
x-18=48
x=48+18
x=66
c,3(x+4)=128-23
3(x+4)=105
x+4= 105:3
x+4=35
x=35-4
x=31
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a) 16x<1284
nên (24)x<(27)4
24x<228
vậy x thuộc 1, 2, 3, 4, 5, 6
b)chứng minh tương tự
chú ý 100...0(18 chữ số 0) là 1018
Kết quả 53x+3<=518
hay 3x+3<18
vậy x thuộc 1, 2, 3, 4
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Ta có:
\(16^x<128^4\Rightarrow2^{4x}<2^{28}\Rightarrow4x=28\Rightarrow x=7\)
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}\Rightarrow5^{3x+3}\le5^{18}\Rightarrow3x+3\le18\Rightarrow x\le5\)
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\(\left[x-36\right]:18=12\)
\(x-36=12.18\)
\(x-36=216\)
\(x=216+36\)
\(x=252\)
\(\left[2x+1\right]^3=125\)
\(\left[2x+1\right]^3=5^3\)
=> \(2x+1=5\)
\(2x=5-1\)
\(2x=4\)
\(x=4:2=2\)
\(2^x.4=128\)
\(2^x=32\)
\(2^x=2^5\)
=> \(x=5\)
\(x^{50}=x\)
\(x=1\)
hoặc
\(x=0\)
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\(2^x.4=128\)
\(\Rightarrow2^x=32\left(\text{cùng chia cho 4}\right)\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
128 - 3 ( x + 4 ) = 18
<=> 3 ( x + 4 ) = 128 - 18
<=> 3 ( x + 4 ) = 110
<=> x + 4 = 110/3
<=> x = 98/3