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5x + 3x + 6x = 280
14x = 280
x = 280 : 14
x = 20
Vậy x = 20
( 2x - 18 ) - 125 = 325
( 2x - 18 ) = 325 + 125
2x - 18 = 450
2x = 450 + 18
2x = 468
x = 234
Vậy x = 234
\(5x+3x+6x=280\)
\(\Rightarrow x\left(5+3+6\right)=280\)
\(\Rightarrow x.14=280\)
\(\Rightarrow x=20\)
b, \(\left(2x-18\right)-125=325\)
\(\Rightarrow2x-18=450\)
\(\Rightarrow2x=468\)
\(\Rightarrow x=234\)
\(A=\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{1-\frac{1}{15}+\frac{1}{125}}{\frac{4}{5}-0,16+\frac{4}{125}}-\frac{4}{625}\)
\(A=\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{4\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}+\frac{1-\frac{1}{15}+\frac{1}{125}}{4\left(\frac{1}{5}-\frac{1}{15}+\frac{1}{125}\right)}-\frac{4}{625}\)
\(A=\frac{1}{2}-\frac{4}{625}\)
\(A=\frac{625-8}{1250}=\frac{617}{1250}\)
18^3 : 9^3 = 5832 : 729 = 8
125^3 : 25^3 = (5^3)^3 : (5^2)^3 = 5^9 : 5^6 = 5^3 = 125
có quy luật hay lắm
\(18^3:9^3=\left(18:9\right)^3=2^3=8\)
\(125^3:25^3=\hept{\begin{cases}\left(5^3\right)^3:\left(5^2\right)^3=5^9:5^6=5^3=125\\\left(5^3\right)^3:\left(5^2\right)^3=\left(5^3:5^2\right)^3=5^3=125\end{cases}}\)chọn cách nào thì tùy bạn
\(\left(10^3+10^4+125^3\right):5^3=\left[10^3+10^3.10+\left(5^2\right)^3\right]:5^3\)
\(=\left(10^3.11+5^6\right):5^3\)
\(=10^3.11:5^3+5^6:5^3\)
\(=\left(10^3:5^3\right).11+5^3\)
\(=2^3.11+5^3\)
\(=88+125=213\)
\(\left(2^{43}+2^4\right):\left(2^{39}+1\right)=\)tương tự mà làm
\(\left(3^4\right)^{31}.3\)\(và\)\(\left(4^3\right)^{31}\)
\(81^{31}.3\)và \(64^{31}\)
\(\Rightarrow3^{125}>4^{93}\)
Có: 3125=(34)31.3=8131.3
493=(43)31=6431
Vì 8131>6431
=>8131.3>6431
=>3125>493
\(4^8.2^{20}.9^{12}.27^5.81^4.25^{20}.125^4\)
\(=\left(2^2\right)^8.2^{20}.\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4.\left(5^2\right)^{20}.\left(5^3\right)^4\)
\(=2^{16}.2^{20}.3^{15}.3^{16}.5^{40}.5^{12}\)
\(=2^{16+20}.3^{15+16}.5^{40+12}\)
\(=2^{36}.3^{31}.5^{52}\)
\(2\dfrac{1}{3}-125\%.x=\dfrac{1}{4}\)
⇒ \(\dfrac{7}{3}-\dfrac{125}{100}.x=\dfrac{1}{4}\)
⇒ \(\dfrac{5}{4}x=\dfrac{28}{12}-\dfrac{3}{12}\)
⇒ \(\dfrac{5}{4}x=\dfrac{25}{12}\)
⇒ \(x=\dfrac{25}{12}.\dfrac{4}{5}\)
⇒ \(x=\dfrac{100}{60}\) \(=\dfrac{5}{3}\)
Vậy \(x=\dfrac{5}{3}\).
\(2\dfrac{1}{3}\) - 125% . x = \(\dfrac{1}{4}\)
=> \(\dfrac{7}{3}\) - \(\dfrac{125}{100}\) . x = \(\dfrac{1}{4}\)
=> \(\dfrac{5}{4}x\) = \(\dfrac{28}{12}\) - \(\dfrac{3}{12}\)
=> \(\dfrac{5}{4}x\) = \(\dfrac{25}{12}\)
=> \(\dfrac{25}{12}\). \(\dfrac{4}{5}\)
=> \(\dfrac{100}{60}\)\(=\dfrac{5}{3}\)
x = \(\dfrac{5}{3}\)
\(5^{17}\)
tích nha nha nha nha
Làm ơn đi đi đi
Tớ sẽ đền ơn
Ở giữa chắc là dấu nhân :?
\(125^3.25^4\)
\(=1953125.390625\)
\(=762939453125\)