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1+2+3+4+5+...+x=210
Ta có :
(SHC+SHĐ).SSH:2
=> Áp dụng công thức :
\(\left(x+1\right).x:2=210\)
\(\Rightarrow\left(x+1\right).x=420\)
\(420=21.20\)
=> x=20
1 + 2 + 3 + 4 + ... + x = 210
=> (1 + x).x:2 = 210
=> (1 + x).x = 210.2
=> (1 + x).x = 420
=> (1 + x).x = 21.20
=> x = 20
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=14/15*20/21*...*209/210
\(=\dfrac{4\cdot7}{5\cdot6}\cdot\dfrac{5\cdot8}{6\cdot7}\cdot...\cdot\dfrac{19\cdot22}{20\cdot21}\)
\(=\dfrac{4\cdot5\cdot6\cdot...\cdot19}{5\cdot6\cdot7\cdot...\cdot20}\cdot\dfrac{7\cdot8\cdot9\cdot...\cdot22}{6\cdot7\cdot8\cdot...\cdot21}=\dfrac{11}{15}\)
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\(B=\frac{3}{1}+\frac{3}{3}+\frac{3}{6}+...+\frac{3}{210}\)
\(=\frac{6}{2}+\frac{6}{6}+\frac{6}{12}+...+\frac{6}{420}\)
\(=\frac{6}{1.2}+\frac{6}{2.3}+\frac{6}{3.4}+...+\frac{6}{20.21}\)
\(=6\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{20}-\frac{1}{21}\right)\)
\(=6\left(1-\frac{1}{21}\right)\)
\(=6.\frac{20}{21}=\frac{40}{7}\)
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( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 210 ) + ( x + 211 ) = 23632
x + 1 + x + 2 + x +3 + .... + x + 210 + x + 211 = 23632
( x + x + x + .... + x ) + ( 1 + 2 + 3 + ... + 210 + 211 ) = 23632
211x + 22366 = 23632
211x = 23632 - 22366
211x = 1266
=> x = 1266 : 211 = 6
Vậy x = 6
ta có (x+1) + (x+2) + (x+3) + ... + (x+210) + (x+211) = 23632
= X + ( 1 + 2 +3 + 4 + .... + 210 + 211 ) = 23632
= X + ( 1 + 211 ) + ( 2 + 210 ) + .... =23632
= X + 212 x 105 =23632
= X + 22260 = 23632
= X = 23632 - 22260
= X = 1372
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b) ( x + 1 ) + ( x +2 ) + ( x + 3 ) + ..... + ( x + 99 ) =6130
( x + x + ... + x ) + ( 1 + 2 + 3 +... + 99 ) =6130
99 × x + 4950 =6130
99 × x = 6130 - 4950
99 × x = 1175
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A=1/2x2/3x3/4x...x2018/2019x2019/2020=1/2020
A = 1/2 x 2/3 x 3/4 x ... x 2018/2019 x 2019/2020 = 1/2020
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\(\frac{1}{3}+\frac{3}{35}< \frac{x}{210}< \frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)
\(\frac{44}{105}< \frac{x}{210}< \frac{158}{105}\)
\(\frac{88}{210}< \frac{x}{210}< \frac{316}{210}\)
suy ra x = { 89:90;91;............315}
1/3+3/35<x/210<4/7+3/5+1/3
=>44/105<x/210<158/105
=>88/210<x/210<316/210
=>x thuộc {89;90;91;92;...;313;314;315}
k nha bn
Dãy trên có số số hạng là:
\(\left(x-1\right):1+1=x\)
Tổng của dãy số trên là:
\(\left(1+x\right)\times x:2=210\)
=> \(\left(1+x\right)\times x=210\times2\)
=> \(\left(1+x\right)\times x=420\)
Vì: \(20\times21=420\Rightarrow x=20\)
mik ko chắc mình đã đúng đâu