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ta thay day so tren la day so tu nhien lien tiep bat dau tu 1 va ket thuc la 100 nen co 100 so hang
tong la (100+1) x 100 :2=5050
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ... + 301 + 302 (có 302 số; 302 chia 4 dư 2)
= 1 + (2 - 3 - 4 + 5) + (6 - 7 - 8 + 9) + ... + (288 - 299 - 300 + 301) + 302
= 1 + 0 + 0 + ... + 0 + 302
= 1 + 302
= 303
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ....... +301 + 302 ( có 302 số : 302 chia 4 dư 2 )
= 1 + ( 2 - 3 - 4 + 5 ) + ( 6 - 7 - 8 + 9 ) + ..... + ( 288 - 299 -300 + 301 ) + 302
= 1 + 0 + 0 + ......... + 0 + 302
= 1 + 302
= 303
Tính nhanh
19 + 18 + 17 + 16 + 14 + 21 + 22 + 23 + 24 + 25 + 26
1/3 + 1/4 + 1/5 + 4/6 + 9/12 + 16/20
\(19+18+17+16+14+21+22+23+24+25+26\)
\(=\left(19+21\right)+\left(18+22\right)+\left(17+23\right)+\left(16+24\right)+\left(14+26\right)+25\)
\(=30+30+30+30+30+25\)
\(=175\)
\(\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{4}{6}+\dfrac{9}{12}+\dfrac{16}{20}\)
\(=\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{4}{5}\)
\(=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)\)
\(\text{=}1+1+1\)
\(\text{=}3\)
a) 19 x 64 + 76 x 34
= 19 x 64 + 19 x 4 x 34
= 19 x ( 64 + 34 x 4 )
= 19 x 200
= 3800
b ) 135 x 12 + 165 x 13
= 135 x 12 + 165 x ( 12 + 1 )
= 135 x 12 + 165 x 12 + 165
= 12 x ( 135 + 165 ) + 165
= 12 x 300 + 165
= 3600 + 165
= 3765
c ) 136 x 68 + 16 x 272
= 136 x 68 + 32 x 136
= 136 x ( 68 + 32 )
= 136 x 100
= 13600
d ) 1 + 2 + 3 + 4 + ...... + 19 + 20
= ( 1 + 20 ) x 20 : 2
= 21 x 10
= 210
e ) 1 + 3 + 5 + ......+ 17 + 19
= 10 : 2 x ( 1 + 19 )
= 5 x 20
= 100
f ) 2 + 4 + 6 + ..... + 18 + 20
= ( 20 + 2 ) x 10 : 2
= 22 x 5
= 110
1+2+3+4+5+...+15+16+17+18+19+20
= ( 1 + 19 ) + ( 2 + 18 ) + ( 3 + 17 ) + ( 4 + 16 ) + ( 5 + 15 ) + ... + ( 9 + 11 ) + ( 10 + 20 )
= 20 + 20 + 20 + 20 + ... + 20 + 30
= 180 + 30 = 210
Tính số phần tử: \(\text{1+2+3+4+...+18+19+20}\)
\(=\left(20-1\right):1+1\) \(=20\)
Tổng : \(\dfrac{\left(20+1\right)\times20}{2}=210\)
(1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+20
=20+20+20+20+20+20+20+20+20+20
=20x10
=200
(15x1-15) x) (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= (15-15) x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0 x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0
= (15 - 15)\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0
204 là kết quả của mình
Đặt A=1+2+3+...+20
A có: (20-1)+1=20(số hạng)
A=(20+1)*20/2=210
Vậy 1+2+3+...+20=210