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b,21/17x13/14x56x3/42
=21/17x3/42x56x13/14
=21x3/17x42 x 56x13/14
=21x3/17x21x2 x 14x4x13/14
=3/17x2 x 4x13
=3/24 x 52=3x52/24
=3x52/3x8
=52/8=13/2
a, 6/7 x 16/15 x 7/6 x 21/32
=(6/7 x 7/6)x16/15x21/32
=16/15x21/32
=16x21/15x32
=16x3x7/3x5x16x2
=7/5x2=7/10
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\(\frac{1\times2\times25}{6\times5\times7}\)\(=\frac{1\times2\times5\times5}{2\times3\times5\times7}=\frac{5}{3\times7}=\frac{5}{21}\)
1/6×2/5×25/7=
rut gon:25(tử)÷5 (mâu), 6 (tử)÷2 (mau)
được
1/3×1/1×5/7=5/21
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\(a.\dfrac{3\times4\times7}{12\times8\times9}=\dfrac{3\times4\times7}{3\times4\times4\times2\times9}\\ =\dfrac{7}{4\times2\times9}=\dfrac{7}{72}\\ b.\dfrac{4\times5\times6}{12\times10\times8}=\dfrac{4\times5\times2\times3}{4\times3\times5\times2\times4\times2}=\dfrac{1}{8}\\ c.\dfrac{5\times6\times7}{12\times14\times15}=\dfrac{5\times6\times7}{2\times6\times7\times2\times5\times3}\\ =\dfrac{1}{2\times2\times3}=\dfrac{1}{12}\)
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1.
a. 455
b. 600
2.
x = - 5 nhưng nếu đây thực sự là toán 4 thì ko tồn tại x
kb vs mk nhe
Bài 1:
a,Ta thấy:QLC là 1
SSH là:(50-41):1+1=10(số)
Tổng là:(41+50):10+1=455
b,45.6+55.6=(45+55)6=100.6=600
Bài 2:
50+x-5=3+37
50+x-5=40
50+x=45
x=45-50=-5
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1616x 2 + 1616x 3 + 1616x 4 +1616x 1
= 2/6 + 3/6 + 4/6 + 1/6
= 10/6
= 5/3
1/6 x 2 + 1/6 x 3 + 1/6 x 4 + 1/6 x 1
= 1/6 x ( 2 + 3 + 4 + 1 )
= 1/6 x 10 = 10/6 = 5/3
đ/s: 5/3
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121 x 6 + 32 x 6 - 53 x 6
= (121 + 32 - 53) x 6
= 100 x 6
= 600
~HT~