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Số hạng thứ 120 là:
(120-1)x2+12=410
=> Công thức
(n-1)*khoảng cách+số đầu
\(284:\left[314-\left(x+3\right)\right]=12.\)
\(\Leftrightarrow\left[314-\left(x+3\right)\right]=\frac{71}{3}\)
\(\Leftrightarrow\left(x+3\right)=\frac{871}{3}\)
\(\Leftrightarrow x=\frac{862}{3}\)
\(14.\left[251-\left(x-5\right)\right]=1470\)
\(\Leftrightarrow\left[251-\left(x-5\right)\right]=105\)
\(\Leftrightarrow x-5=146\)
\(\Leftrightarrow x=151\)
\(\left(120+x\right):x-15=16\)
\(\Leftrightarrow\left(120+x\right):x=31\)
\(\Leftrightarrow\left(120+x\right).\frac{1}{x}=31\)
\(\Leftrightarrow\frac{1}{x}.x+120x=31\)
\(\Leftrightarrow1+120x=31\)
\(\Leftrightarrow120x=30\)
\(\Leftrightarrow x=4\)
\(\left(135-x\right):x+24=28\)
\(\Leftrightarrow\left(135-x\right):x=4\)
\(\Leftrightarrow\left(135-x\right).\frac{1}{x}=4\)
\(\Leftrightarrow\frac{1}{x}.135-\frac{1}{x}x=4\)
\(\Leftrightarrow\frac{1}{x}135-1=4\)
\(\Leftrightarrow\frac{1}{x}135=5\)
\(\Leftrightarrow\frac{1}{x}=\frac{1}{27}\)
\(\Leftrightarrow x=27\)
[( 314.69 + 314.120 ) : 316 - 7] : 24
= [ 314.( 69 + 120) : 316 - 7] : 24
= [ 189 : 32 - 7] : 24
= [ 21 - 7]: 24
= 14 : 16
= \(\dfrac{7}{8}\)
(x-14)-20=5
=> x-14 = 25
=> x = 39
Các dạng toán như này lớp 6 ai cũng làm được cả * lười vừa thôi*
a) (14 + 38 + 66) - (10 + 4 - 16)
= 14 + 38 + 66 - 10 - 4 + 16
= (14 - 4) + (66 + 38 + 16) - 10
= 10 + 120 - 10
= 120
b) (70 + 20 - 60) - (-30 - 80 + 120)
= 70 + 20 - 60 + 30 + 80 - 120
= (70 + 30) + (20 + 80) - (120 + 60)
= 100 + 100 - 180
= 200 - 180
= 20
a, (14 + 38 + 66) - (10 + 4 - 16)
= 14 + 38 + 66 - 10 - 4 + 16
= (14 - 4 - 10) + (38 + 66 + 16)
= 0 + 120
= 120
\(\frac{x+22}{11}+\frac{x+23}{12}=\frac{x+24}{13}+\frac{x+25}{14}\)
\(\Leftrightarrow\left(\frac{x+22}{11}+1\right)+\left(\frac{x+23}{12}+1\right)=\left(\frac{x+24}{13}+1\right)+\left(\frac{x+25}{14}+1\right)\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}=\frac{x+37}{13}+\frac{x+39}{14}\)
\(\Leftrightarrow\frac{x+33}{11}+\frac{x+35}{12}-\frac{x+37}{13}-\frac{x+39}{14}=0\)
\(\Leftrightarrow\frac{2184\cdot\left(x+33\right)+2002\cdot\left(x+35\right)-1848\cdot\left(x+37\right)-1716\cdot\left(x+39\right)}{24024}=0\)
\(\Leftrightarrow2184x+72072+2002x+70070-1848x-68376-1716x-66924=0\)
\(\Leftrightarrow622x+6842=0\)
\(\Leftrightarrow x=-11\)
(x - 59).16 - 8 = 120
=> (x - 59).16 = 120 + 8
=> (x - 59).16 = 128
=> x - 59 = 128 : 16
=> x - 59 = 8
=> x = 8 + 59 = 67
Vậy x = 67
[x-59].16-8=120
[x-59].16 =120+8
[x-59].16 =128
x-59 =128:16
x-59 =8
x =8+59
x =67
k cho mình nha
A) 3 . \(5^2\)- 16 : \(2^2\)= 3 . 25 - 16 : 4 = 75 - 4 = 71
B) 20 - [30-(5-\(1^2\)) ] = 20 - [30- (5-1) = 20 - [30 - 4 ] = 20 - 26 = -6
C) 22 . 7 - 23 . 14 = 22 . 17 - 8 = 364 - 8 = 356
D) 17.85 + 15.17-120 = 17 . ( 85 + 15 ) -120= 17 . 100 -120 = 1700 - 120 = 1580
k cho mính nhé bn
Bài 1:
a) =25,97+(6,54+103,46)
=25,97+110
=135,97
b)136x75+75x64
=75x(136+64)
=75x200
=15 000
c) (21/8+1/2):5/16
=(21/8+4/8)x16/5
=25/8x16/5
=10
d)3/17-4/5+14/17
=(3/17+14/17)-4/5
=1-4/5
=1/5
Bài 2:
a)720:\([41-(2x-5)]\)=120
41 - (2x-5) =720:120
41 - (2x-5) =6
2x-5 =41-6
2x-5 =35
2x =35+5
2x =40
x =40:2
x =20
b)2/3 x X +3/4=3
2/3 x X =3-3/4
2/3 x X =12/4-3/4
2/3 x X =9/4
x =9/4:2/3
x =9/4x3/2
x =27/8
c) x+0,34=1,19x1,02
x+0,34=1,2138
x =1,2138-0,34
x =0,8738
ta có :
\(\left(-120\right):X-16=14\Leftrightarrow\left(-120\right):X=14+16=30\)
vậy \(X=-120:30=-4\)