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<=> |x+2| = 13
<=> \(\orbr{\begin{cases}x+2=13\\x+2=-13\end{cases}\Rightarrow}\orbr{\begin{cases}x=11\\x=-15\end{cases}}\)
Vậy.........
hok tốt
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\(|x+2|=12+\left(-3\right)+\left|-4\right|\)
\(|x+2|=12-3+4\)
\(\left|x+2\right|=13\)
\(\Rightarrow x\in\left\{-15;11\right\}\)
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\(a)\frac{2}{3}x-\frac{1}{2}=\frac{5}{12}\)
\(\Rightarrow\frac{2}{3}x=\frac{5}{12}+\frac{1}{2}=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}:\frac{2}{3}=\frac{11}{8}\)
\(b)\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\Rightarrow\frac{14}{5}x-50=51.\frac{2}{3}=34\)
\(\Rightarrow\frac{14}{5}x=34+50=84\)
\(\Rightarrow x=84:\frac{14}{5}=30\)
a) 2/3.x - 1/2 = 5/12
2/3.x = 5/12 + 1/2
2/3.x = 11/12
x = 11/12 : 2/3
x = 11/8
b) \(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
\(\frac{14}{5}.x-50=51.\frac{2}{3}\)
\(\frac{14}{5}.x-50=34\)
\(\frac{14}{5}.x=34+50\)
\(\frac{14}{5}.x=84\)
\(x=84:\frac{14}{5}\)
\(x=30\)
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a) Đặt \(A=|x-2|-12\)
Ta có: \(|x-2|\ge0\forall x\)
\(\Rightarrow|x-2|-12\ge0-12\)
Hay \(A\ge-12\)
Dấu "=" xảy ra \(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=2\)
Vậy Min A =-12 \(\Leftrightarrow x=2\)
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a) xy - x - y = 10
x.(y-1)-y = 10
x.(y-1)-(y-1)=9
(y-1).(x-1) = 9
=>y-1 và x-1 thuộc Ư(9)
Sau đó tìm Ư(9) và thay vào, tìm ra số còn lai
Phần b) c) cx lm tương tự , có j ib cho m , tk mk nữa nhé !
Duyệt đi , chúc bạn hk giỏi
Sai rồi bn, mình thử lại chỉ ra kết quả bằng 8 thôi, bạn xem lại đi.
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Qui đồng rồi khử mẫu, ta được:
\(4x+12.\left(27-x\right)=15x+5.\left(27-x\right)\)
\(\Leftrightarrow4x+324-12x=15x+135-5x\)
\(\Leftrightarrow4x-12x-15x+5x=135-324\)
\(\Leftrightarrow-18x=-189\Leftrightarrow x=\frac{21}{2}=10,5\)
Vậy x = 10,5
\(\frac{x}{15}+\frac{27-x}{5}=\frac{x}{4}+\frac{27-x}{12}\)
\(\frac{x}{15}+\frac{3\left(27-x\right)}{15}=\frac{3x}{12}+\frac{27-x}{12}\)
\(\frac{x}{15}+\frac{81-3x}{15}=\frac{3x}{12}+\frac{27-x}{12}\)
\(\frac{x+81-3x}{15}=\frac{3x+27-x}{12}\)
\(\frac{-2x+81}{15}=\frac{2x+27}{12}\)
\(12\left(-2x+81\right)=15\left(2x+27\right)\)
\(-24x+972=30x+405\)
\(972-405=30x+24x\)
\(567=54x\)
\(x=567:54\)
\(x=10,5\)
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\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
Vì \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\)
=> x+1 =0
=> x =-1
TL:
12 chia hết cho x
=> x thuộc : { 1;2;3;4;6;12;-12;-6;-4;-3;-2;-1;0}
_HT_ nha
\(12\)\(⋮\)\(x\)
\(\Rightarrow\)\(x\inƯ\left(12\right)\)
\(\Rightarrow\)\(x\in\left\{1;2;3;4;6;12\right\}\)